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2 years ago

How to you solve g, 2/5g = 3/5

Mathematics

1 answer:

Romashka [77]2 years ago

3 0

2/5g=3/5 multiply both sides by the reciprocal of 2/5 g=(3/5) (5/2) g=3/2

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I need help pleaseeeee!!!

Damm [24]

Answer:

y=7

Step-by-step explanation:

look at 3 on x axis and find y value (the point of the line)

4 0

2 years ago

Read 2 more answers

Uesday Write 784,000 in each form, Word: Expanded

balandron [24]

Standard: 784,000

Word: seven hundred eighty-four thousand

Expanded: (700,000) + (80,000) + (4,000)

8 0

2 years ago

Jamal recorded the daily high temperatures over a two week period

lorasvet [3.4K]

Answer:

A. 4

Step-by-step explanation:

First rearrange the temperatures from low to high

60, 65, 68, 69, 69, 70, 70, 70, 71, 71, 73, 74, 75, 77

There are 14 data,

Q1 = 4th data = 69

Q3 = 11th data = 73

Interquartile range = Q3 - Q1 = 73 - 69 = 4

5 0

1 year ago

Work out the area of the trapezium ABDE. B 9 cm 6 cm 8 cm →D E

Evgen [1.6K]

Answer:

Area of the trapezium ABDE = 30 cm²

Step-by-step explanation:

Area of a trapezium = $\frac{1}{2}(b_1+b_2)h$

Here, $b_1$ and $b_2$ are the parallel sides of the trapezium

h = Distance between the parallel sides

From the picture attached,

ΔCAE and ΔCBD are the similar triangles.

So by the property of similarity their sides will be proportional.

$\frac{AE}{BD}= \frac{CE}{CD}$

$\frac{9}{6}=\frac{CE}{8}$

CE = $\frac{9\times 8}{6}$

CE = 12 cm

Therefore, DE = CE - CD

DE = 12 - 8 = 4 cm

Now area of trapezium ABDE = $\frac{1}{2}(AE+BD)(DE)$

= $\frac{1}{2}(6+9)4$

= 30 cm²

Therefore, area of the trapezium ABDE = 30 cm²

8 0

2 years ago

Pls help me with this pre-calc question on vectors!!

alexdok [17]

E = (-12,15,-9)
F = (-12, 17 , -22 )
EF = F - E = (-12, 17 , -22 ) - (-12,15,-9)
= ( 0 , 2 , -13 ) = 2j - 13 k
The correct answer is option C

6 0

2 years ago