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3 years ago

When will The Ghost of Christmas present cease to exist?

Mathematics

1 answer:

bazaltina [42]3 years ago

7 0

Answer:

never ever not in a million years

Step-by-step explanation:

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Step-by-step explanation:

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4 years ago

Please please please help

Semmy [17]

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4 years ago

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3 years ago

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What is the value of the following expression when b = -2 and C = 3? -12b + 5c - 15

zysi [14]

Answer:

-24

Step-by-step explanation:

12(-2)+5(3)-15

-24+15-15

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4 0

3 years ago

What is lim x→3 x^2 - x - 6/ x - 3

Kisachek [45]

<h3>Answer: D) 5</h3>

=======================================================

Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, $\frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2$

Allowing us to say,

$\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\$

5 0

4 years ago

When will The Ghost of Christmas present cease to exist? ​

When will The Ghost of Christmas present cease to exist?