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Alona [7]
3 years ago
6

Geckos and iguanas are both lizards. The length of an average gecko is about three quarters of the length of an average iguana.

Geckos are about 15 in. long. What is the length of an average iguana?
Mathematics
2 answers:
GREYUIT [131]3 years ago
5 0

Answer:

20in

Step-by-step explanation:

The lenght of am average iguana is 20 in.

andre [41]3 years ago
4 0
20 in. Because if you divide it by three then multiply it by four you get your answer.
You might be interested in
I'm stuck on this homework question. I forgot the formula to find the side. This is 9th grade geometry.
dexar [7]

Answer:

x = 2root(22)

see image.

Step-by-step explanation:

The triangle shown is one big triangle cut into two more smaller triangles: one medium-sized and one smaller.

ALL THREE TRIANGLES ARE SIMILAR BY AA.

Set the two smaller triangles up so you can see the corresponding sides. x is the short leg in one triangle and it is the long leg in the smallest triangle. Set up a proportion.

22/x = x/4

crossmultiply

x^2 = 22•4

x^2 = 88

square root both sides.

x = sqroot(88)

x = 2sqroot(22)

see image.

3 0
2 years ago
PLEASE HELP AND EXPLAIN!
Neko [114]

Answer:

12 years old.

Step-by-step explanation:

1) 2x+x=18

2) Now solve 2x+x=18

Add alike terms

3x=18

Now divide both sides by 3 (3x/3 and 18/3)

x=6

So Hannah is 6 years old. Her sister must be 12.

8 0
2 years ago
A baseball is thrown without any spin. Would you consider the baseball to be in motion?
liq [111]

Answer:

yes

Step-by-step explanation:

5 0
3 years ago
National statistics show that 23% of men smoke and 18.5% of women smoke. A random sample of 175 men indicated that 45 were smoke
NeTakaya

Answer:

98% C.I. = [-0.1270, 0.0994]

Step-by-step explanation:

Here

p1= proportion of men smokers

p1= 45/175= 0.2571

p2= proportion of women smokers

p2= 42/155= 0.2709

1)  Choose the significance level ∝= 0.02

2) The formula for confidence interval is

(p1^- p2^)- z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

and

(p1^- p2^) z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

<u>3)  The z value is 2.05</u>

<u>4) Calculations:</u>

(p1^- p2^)- z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

Putting the values

= 0.2571-0.2709)(-2.05) sqrt ( 0.2571(1-0.2571)/175+ 0.2709(1-0.2709)/155)

=-0.1270 ( using calculator)

And

(p1^- p2^)z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

Putting the values

= 0.2571-0.2709)(2.05) sqrt ( 0.2571(1-0.2571)/175+ 0.2709(1-0.2709)/155)

=0.0994  ( using calculator)

and Putting ± 2.05 in the confidence interval formula we get limits (-0.1270, 0.0994)

6 0
3 years ago
X+y+z=10<br> 6x+y+2z=37<br> y-z=10
garik1379 [7]
Ignore the scribbles
Search up Elimination and substitution

7 0
2 years ago
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