F=\dfrac{9}{5}C+32\\\\A.\\\dfrac{9}{5}C+32=F\ \ \ |-32\\\\\dfrac{9}{5}C=F-32\ \ \ |\cdot\dfrac{5}{9}\\\\C=\dfrac{5}{9}(F-32)
B.\\F=212\to C=\dfrac{5}{9}(212-32)=\dfrac{5}{9}\cdot180=100\\\\212^oF=100^oC
C.\\F=80\to C=\dfrac{5}{9}(80-32)=\dfrac{5}{9}\cdot48\approx26.7\\\\80^oF\approx26.7^oC
First let
, so that
to write the integral as
Now recall that
, so substituting
should do the trick. The integral then becomes
Answer:
11x 5 =55-22=33
Step by step explanation
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Answer:3.25
Step-by-step explanation:
30-17=13 13 divied by 4 = 3.25
