Can someone please help me with this question?

In ΔOPQ, the measure of ∠Q=90°, the measure of ∠O=76°, and OP = 7.3 feet. Find the length of PQ to the nearest tenth of a foot..

PSYCHO15rus [73]

Answer: 7.1 feet

Step-by-step explanation: I guessed lol

6 0

2 years ago

What are some of the reasons for Venus’s high temperatures?

Tems11 [23]

Answer:

As sunlight passes through the atmosphere, it heats up the surface of Venus. Most of this heat cannot escape back into space because it is blocked by the very thick atmosphere of Venus. The heat becomes trapped and builds up to extremely high temperatures

Step-by-step explanation:

im not sure if that is what you are looking for but there

7 0

2 years ago

11

BaLLatris [955]

<h3>Answer:</h3>

x=30

<h3>Solution:</h3>

First, use the distributive property:
8x-3(2x-4)=3(x-6)
8x-6x+12=3x-18
Simplify:
2x+12=3x-18
2x-3x=-12-18
-x=-30
x=30

Hope it helps.

Do comment if you have any query.

8 0

1 year ago

It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i

USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 55, \pi = \frac{24}{55} = 0.4364$

93% confidence level

So $\alpha = 0.07$ , z is the value of Z that has a pvalue of $1 - \frac{0.07}{2} = 0.965$ , so $Z = 1.81$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574$

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

8 0

2 years ago

Solve : h /24 = - 6

docker41 [41]

Answer:

h = -144

you multiply 24 and -6 to get -144.

5 0

2 years ago

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