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2 years ago

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emelia earns $8.74 per hour plus a gas allowence of $3.50 per day at her job how much does Emelia jobs pays in a day when she wo

rks 5 1/2 hours? write an expression and evaluate for 5 1/2 hours

1 answer:

trapecia [35]2 years ago

8 0

Answer:

8.74 (3.50) + 3.50

= $51.57

Step-by-step explanation:

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A plane travels 3,625.26 miles in 6.9 hours. What is the plane’s unit rate?

Lunna [17]

Answer:

The correct answers are:

a) $\frac{3625.26 miles}{6.9hours}$

b)36252.6 tenths miles÷ 69 tenths hours

c) $\frac{3500miles}{7hours}= 500\frac{miles}{hour}$

d) $\frac{3625.26miles}{6.9hours} \frac{10}{10} =\frac{36252.6miles}{69hours}$

e) 525.4 miles/h

Step-by-step explanation:

The division is solved by using the division algorithm in the attached picture.

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3 years ago

Can anyone answer this pls!!!!!!!!!!

gizmo_the_mogwai [7]

u₁₂ represents the amount of loan remaining after 12 years

<h3>How to interpret u₁₂?</h3>

The function is given as:

u₀ = 8000

$u_n = u_{n-1}(1 + 0.054) - 500$

Given that the subscript n in $u_n$ represents number of years and $u_n$ represents the amount left to be paid after n years.

We can conclude that:

u₁₂ represents the amount of loan remaining after 12 years

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1 year ago

What is 64 thousandths in decimal form

shusha [124]

I am pretty sure it is 0.064. Hope this helps

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3 years ago

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Please help me solve this step by step please!!

qaws [65]

Answer:

7^(1-3+1) = 7^-3

Step-by-step explanation:

Here is the rule you should know: when multiplying powers of the same base you add the exponents ans when dividing powers of the same base you subtract the exponents.

Also, if there is no number at the exponent, it is 1.

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3 years ago

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The line integral of xydx×x^2y^3dy where c is the triangle with points (0,0) (1,0) (1,2) using green's theorem

lyudmila [28]

If $\mathcal C$ is the boundary of the triangle $D$ , then by Green's theorem

$\displaystyle\int_{\mathcal C}xy\,\mathrm dx+x^2y^3\,\mathrm dy=\iint_D\left(\frac{\partial(x^2y^3)}{\partial x}-\frac{\partial(xy)}{\partial y}\right)\,\mathrm dA$
$=\displaystyle\int_{x=0}^{x=1}\int_{y=0}^{y=2x}(2xy^3-x)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x\int_{y=0}^{y=2x}(2y^3-1)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x(8x^4-2x)\,\mathrm dx=\frac23$

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2 years ago