Answer:
Probability that at least one of them will be affected = 3/16 + 3/16 + 1/16 = 7/16
Explanation:
If both parents are heterozygous for a genetic disease; Xx and Xx
The offspring's they will produce will be as follows ; XX, Xx, xX, xx
- Probability that first child will be affected = 1/4
- Probability that first child will not be affected = 1 - 1/4 = 3/4
- Probability that first child have it and second does not = 1/4 x 3/4 = 3/16
- Probability that first child does not have it, second child have it = 3/4 x 1/4 = 3/16
- Probability that both of them will have it = 1/4 x 1/4 = 1/16
- Hence, Probability that at least one of them will be affected = 3/16 + 3/16 + 1/16 = 7/16
Black hair because a phenotype is physical characteristics of an organism.
Answer:
you don't earn money while volunteering
volunteering aboard can be expensive
many volunteers have too high expectations
Explanation:
I searched it up and took time to read
Given: The systolic arterial blood pressure observed for 20 dogs is normally distributed with a mean of 152 mm of mercury (Hg) and a standard deviation of 18 mm of Hg.
To find: P(100 < 152)
Method: Calculation of Z-Score followed by the probability or area of the bell curve at X = 100.
Solution:
Mean u = 152, std s = 18
Z score = ![\frac{X-u}{s} = \frac{100-152}{18} = -2.89](https://tex.z-dn.net/?f=%20%5Cfrac%7BX-u%7D%7Bs%7D%20%3D%20%5Cfrac%7B100-152%7D%7B18%7D%20%3D%20-2.89%20%20)
The value of P(100<152) is calculated by looking at the value of Z in the Z score for the standard normal distribution given in the image.
P(Z=-2.89) = 0.0019
The P(Z = -2.89) corresponds to the area in the left tail of the bell curve.
Thus the probability of 100 mm Hg blood pressure is 0.0019.