Do you have a picture of the DNA sequence?
Answer:
meiosis_
fertilization
mitosis
zygote
Explanation:
In life cycles that alternate between haploid and diploid stages, ____meiosis_ acts to reduce the number of chromosomes per cell from two sets to one set. In life cycles that alternate between haploid and diploid stages, ___fertilization__ acts to double the number of chromosome per cell from one set to two sets. In life cycles that alternate between haploid and diploid stages, ______mitosis______ acts to keep the number of chromosomes per cell the same. In animals, a single diploid cell called a ____zygote________ divides by mitosis to give rise to all the cells of the adult body.
Answer:
0.7
Explanation:
Using Hardy-Weinberg equation of genetic variation being constant when disturbing factors such has mutation and others are removed.
p² + pq + q² = 1 and p + q = 1
where p² is the frequency of the homozygous dominant genotype (RR) and q² is the frequency of the homozygous recessive genotype (rr) and 2pq is the frequency of heterozygous genotype (Rr). p represent the frequency of "R" and q represent "g". since the coefficient against the green/green homozygote is 0.30 then
the fitness of the green/green homozygote = 1 - 0.3 = 0.7
