The rest of the question is the attached figure.
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Δ AYW a right triangle at Y ⇒⇒⇒ ∴ WA² = AY² + YW²
And AY = YB ⇒⇒⇒ ∴ WA² = YB² + YW² → (1)
Δ BYW a right triangle at Y ⇒⇒⇒ ∴ WB² = BY² + YW² → (2)
From (1) , (2) ⇒⇒⇒ ∴ WA = WB →→ (3)
Δ CXW a right triangle at Y ⇒⇒⇒ ∴ WC² = CX² + XW²
And CX = XB ⇒⇒⇒ ∴ WC² = XB² + XW² → (4)
Δ BXW a right triangle at Y ⇒⇒⇒ ∴ WB² = XB² + XW² → (5)
From (4) , (5) ⇒⇒⇒ ∴ WC = WB →→ (6)
From (3) , (6)
WA = WB = WC
given ⇒⇒⇒ WA = 5x – 8 and WC = 3x + 2
∴ <span> 5x – 8 = 3x + 2</span>
Solve for x ⇒⇒⇒ ∴ x = 5
∴ WB = WA = WC = 3*5 + 2 = 17
The correct answer is option D. WB = 17
Answer:
You basically answer the problem.
Evaluating is the same as answering
Answer:
Tank B
Step-by-step explanation:
Proportional relationships are relationships between two variables with equivalent ratios. For a proportional relationship, one variable is always a constant value times the other. A line is a proportional relationship if it starts from the origin, but if it does not start from the origin, it is not proportional.
From the two tanks, we can see that tank A have a y intercept whereas tank B starts from the origin. Therefore tank B shows a proportional relationship.
Answer:
hi
Step-by-step explanation:
Answer:
x = 47°
Step-by-step explanation:
From the picture attached,
CPD is a straight line.
Therefore, ∠CPB and ∠DPB is a linear pair of angles.
And linear pair of angles are supplementary.
By the property of linear pair of angles,
m∠CPB + m∠DPB = 180°
133 + x = 180
x = 180 - 133
x = 47°