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3 years ago

What is the answer to m+4=-12

1 answer:

8 0

Hey there!

You need to get m by itself. So subtract 4 on each side. You get m=-16. (-12-4 is the same as -12+-4). Since m is by itself, this is the answer: m=-16.

I hope this helps!

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Substitution method of y=x+5 and 5x+y=3

Levart [38]

To solve by substitution, you need to fill in the value for either x or y. Since y = x + 5, you already have the y value. It's x + 5. Now you need to find x before you can go any further. So let's take 5x + y = 3 and fill x + 5 in for y. 5x + y = 5 5x + x + 5 = 3 Now solve for x. 5x + x + 5 = 3 6x + 5 = 3 6x = 3 - 5 6x = -2 x = -2/6 or -0.33 Now solve x + 5 for y. y = x + 5 y = -0.33 + 5 y = 4.67 So x = -0.33 and y = 4.67

7 0

3 years ago

Read 2 more answers

Could I have some help with the two in the photo please? Thanks.

Westkost [7]

Answer:

a:5√3+3√5

b:4(√2+√7)

Step-by-step explanation:

Used photomath witch is an app that takes pictures of equations and solves them. 100% recommend

3 0

3 years ago

Read 2 more answers

Select the factors that can be divided out to simplify the multiplication problem: 4/26 x 13/20. Select all that apply. A. 2 B.

Tcecarenko [31]

$\dfrac{4}{26} \times \dfrac{13}{20}$

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Divide by factor of 4.
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<em>*Or divide by the factor of 2 twice</em>

$\dfrac{1 \times 4}{26} \times \dfrac{13}{5 \times 4}$

$\dfrac{1}{26} \times \dfrac{13}{5}$

-------------------------------------
Divide by factor of 13.
-------------------------------------

$\dfrac{1}{2 \times 13} \times \ \dfrac{1 \times 13}{5}$

$\dfrac{1}{2} \times \dfrac{1 }{5}$

-------------------------------------
Combine into single fraction.
-------------------------------------
$\dfrac{1}{10}$

--------------------------------------------------------------------------
Answer: The factors are 2, 4 and 13
--------------------------------------------------------------------------

3 0

3 years ago

Read 2 more answers

Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he

alexgriva [62]

Answer:

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

$9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$

$e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) } ]y = 0$

By comparing with y′+p(t)y=g(t), we get

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous.

6 0

2 years ago

|x+1| = 1/5x+1<br> .......................

Mademuasel [1]

Answer:

x=0, -5/3

Step-by-step explanation:

3 0

2 years ago