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Usimov [2.4K]
3 years ago
10

What are the x- and y-intercepts of the graph of 5x + y = 20?

Mathematics
1 answer:
geniusboy [140]3 years ago
4 0

x-intercept: 4

y-intercept: 20

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Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total
dimulka [17.4K]
You can set up a system of equations for this problem. x= number of coach tickets and y = number of first class tickets.

$210x + $1200y = $10,230 (cost of coach ticket plus cost of first class tickets is total budget)

x + y = 11 (number of coach tickets plus number of first class tickets is total number of people)

Solve the second equation for y to get y = 11 - x, then plug that into the first equation and solve for x:

$210x + $1200(11 - x) = $10,230

$210x + $13,200 - $1200x = $10,230

-$990x + $13,200 = $10,230

-$990x = $2,970

x = 3


Sarah bought x = 3 coach tickets. Plug that into the second equation and solve for y:

3 + y = 11

y = 8


Sarah bought y = 8 first class tickets.
6 0
3 years ago
18=30-r30 solve for r
trasher [3.6K]

Answer:

r =

Step-by-step explanation:

r=30√12,−30√12

3 0
3 years ago
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Elodia [21]

Answer:

HUH WHAT DOES THIS MEAN?

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2 years ago
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ms.jones tooke her family to the movies. there were a total of 12 people. children tickets cost $5 and adults tickets cost $10.
solmaris [256]

Answer:

5 children

Step-by-step explanation:

7 adults = $70

5 children = $25

total= 12 people

○○○○○○○○○○○○○○○

therefore 5 children went

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5 0
3 years ago
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Please someone what is the total surface area of this pryamid ​
Dimas [21]

Answer:

\large\boxed{C.\ (25+25\sqrt3)\ in^2}

Step-by-step explanation:

We have the square and four equilateral triangles.

The formula of an area of a squre:

A_S=a^2

a - length of side

The formula of an area of an equilateral triangle:

A_T=\dfrac{a^2\sqrt3}{4}

a - length of side

Clculate the areas:

SQURE:

A_S=x^2\ in^2

TRIANGLE:

A_T=\dfrac{x^2\sqrt3}{4}\ in^2

The SURFACE AREA of a square pyramid:

S.A.=A_S+4A_T\\\\S.A.=x^2+4\cdot\dfrac{x^2\sqrt3}{4}=x^2+x^2\sqrt3

Put x = 5:

S.A.=5^2+5^2\sqrt3=(25+25\sqrt3)\ in^2

7 0
3 years ago
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