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Kazeer [188]
3 years ago
5

2 Points

Mathematics
1 answer:
Mashcka [7]3 years ago
4 0

Answer:

C

Step-by-step explanation:

Factor: -7x^2 -5x+18

Factor -1 out of 7x^2 -5x +18:

−(7x^2+5x−18)

Factor.

1. 18 is negative, so a negative number multiplied by a postive number.

2. You can't factor 7, so 7x times x.

(7x−9)(x+2)

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3 out of 5 picks are orange. if 12 picks are orange haw many picks are in all
xxTIMURxx [149]

Answer:

There were 20 picks total

Step-by-step explanation:

We can use a proportion to solve this problem.  Put the orange picks on top and the total picks on bottom

3 orange         12 orange

-------------- =   ---------------

5 total                x total

Using cross products

3x = 5*12

3x= 60

Divide each side by 3

3x/3 = 60/3

x = 20

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2 years ago
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A real estate agent has 14 properties that she shows. She feels that there is a 50% chance of selling any one property during a
Ratling [72]

Answer:

91.02% probability of selling more than 4 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either it is sold, or it is not. The chance of selling any one property is independent of selling another property. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.5

Compute the probability of selling more than 4 properties in one week.

Either you sell 4 or less properties in one week, or you sell more. The sum of the probabilities of these events is decimal 1. So

P(X \leq 4)  + P(X > 4) = 1

We want to find P(X > 4). So

P(X > 4) = 1 - P(X \leq 4)

In which

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.5)^{0}.(0.5)^{14} = 0.000061

P(X = 1) = C_{14,1}.(0.5)^{1}.(0.5)^{13} = 0.000854

P(X = 2) = C_{14,2}.(0.5)^{2}.(0.5)^{12} = 0.0056

P(X = 3) = C_{14,3}.(0.5)^{3}.(0.5)^{11} = 0.0222

P(X = 4) = C_{14,4}.(0.5)^{4}.(0.5)^{10} = 0.0611

So

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000061 + 0.000854 + 0.0056 + 0.0222 + 0.0611 = 0.0898

Finally

P(X > 4) = 1 - P(X \leq 4) = 1 - 0.0898 = 0.9102

91.02% probability of selling more than 4 properties in one week.

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Answer:

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Total Profit = P(a,b) = ($0.40a) + ($0.40b), where a = # of apples sold and b = # of bananas sold.
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