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4 years ago

0.5x-7= 0.3 solve the equation

Mathematics

1 answer:

Lena [83]4 years ago

3 0

Answer:

<h3> $\boxed{ \bold{ \boxed{ \sf{x = 14.6}}}}$ </h3>

Step-by-step explanation:

$\sf{0.5x - 7 = 0.3}$

Move 7 to right hand side and change it's sign

⇒ $\sf{0.5x = 0.3 + 7}$

Add the numbers

⇒ $\sf{0.5x = 7.3}$

Divide both sides of the equation by 0.5

⇒ $\sf{ \frac{0.5x}{0.5} = \frac{7.3}{0.5} }$

Calculate

⇒ $\sf{x = 14.6}$

Hope I helped!

Best regards!!

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3 years ago

Can some one help me. The QN is SIMPLIFY BY RATIONALISING DENOMINATOR.

WITCHER [35]

Answer:

$\frac{10}{3}$ - $\frac{2\sqrt{7} }{3}$

Step-by-step explanation:

Rationalise the denominator by multiplying the numerator/ denominator by the conjugate of the denominator

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12 / ( $\sqrt{7}$ + 5) × ( $\sqrt{7}$ - 5 ) / ( $\sqrt{7}$ - 5)

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3 years ago

A student repeatedly measures the mass of an object using a mechanical balance and gets the following values: 560 g, 562 g, 556

MrRissso [65]

Answer: 2.76 g

Step-by-step explanation:

The formula to find the standard deviation:-

$\sigma=\sqrt{\dfrac{\sum(x_i-\overline{x})^2}{n}}$

The given data values : 560 g, 562 g, 556 g, 558 g, 560 g, 556 g, 559 g, 561 g, 565 g, 563 g.

Then, $\overline{x}=\dfrac{\sum_{i=1}^{10} x_i}{n}\\\\\Rightarrow\ \overline{x}=\dfrac{560+562+556+558+560+556+559+561+565+563}{10}\\\\\Rightarrow\ \overline{x}=\dfrac{5600}{10}=560$

Now, $\sum_{i=1}^{10}(x_i-\overline{x})^2=0^2+2^2+(-4)^2+(-2)^2+0^2+(-4)^2+(-1)^2+1^2+5^2+3^2\\\\\Rightarrow\ \sum_{i=1}^{10}(x_i-\overline{x})^2=76$

Then, $\sigma=\sqrt{\dfrac{76}{10}}=\sqrt{7.6}=2.76$

Hence, the standard deviation of his measurements = 2.76 g

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4 years ago

0.5x-7= 0.3 solve the equation​

0.5x-7= 0.3 solve the equation