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a_sh-v [17]
3 years ago
15

SAQ 5.1

Mathematics
1 answer:
iVinArrow [24]3 years ago
4 0

Answer:

1. (i) 7, 21, 63, 189

(ii) 20, 10, 5, 2.5

2. (i) n²+n (where n = 1, 2, 3, ..)

(ii) 8/(10^n) (where n = 1, 2, 3, ..)

(iii) 1/(n+1) (where n = 1, 2, 3, ..)

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PLEASE HELP, I don’t know how to do this...like at all
Svet_ta [14]

Answer:

arc ? = 255°

Step-by-step explanation:

arc DB = 180° - 75° = 105°

arc ? = 360° - 105° = 255°

6 0
3 years ago
Use the table to write a quadratic function in vertex form. Then rewrite the function in standard form.
Kisachek [45]

Answer:

Step-by-step explanation:

The graph decreases at first, then changes direction at (2, 5).

y = a(x-2)^2 + 5

Plug in (1,11) and solve for a:

11 = a(1-2)^2 + 5

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Equation in vertex form:

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8 0
3 years ago
Factorise 6+ 9x show working please
Stolb23 [73]
6 + 9x.....a common factor in both terms is 3

3(2 + 3x) <==
5 0
3 years ago
What is the value of the expression below when a = 3 and b = 7?
svp [43]

Answer:

42

Step-by-step explanation:

9^2*7-2*7

56-14

42

I hope this helps.

6 0
3 years ago
Read 2 more answers
Which is equivalent to x^3 y^-7
PilotLPTM [1.2K]

For this case we must find an expression equivalent to:

x ^ 3 * y ^ {- 7}

By definition of power properties we have to meet:

a ^ {-1} = \frac {1} {a ^ 1} = \frac {1} {a}

Then, we can rewrite the expression as:

x ^ 3 * \frac {1} {y ^ 7} =\\\frac {x ^ 3} {y ^ 7}

Answer:

\frac {x ^ 3} {y ^ 7}

8 0
3 years ago
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