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Doss [256]
3 years ago
5

Find the coordinates of the midpoint of the segment with endpoints A(-5, 6) and B(3, 2). You must show all work in order to rece

ive credit!
Mathematics
1 answer:
OLga [1]3 years ago
4 0
Midpoint Formula = M = ( \frac{ x_{1}+x_{2}}{2}) + ( \frac{ y_{1} + y_{2}} {2})

We are given the coordinates: A(-5,6) and B(3,2)
Plug the values into the equation to get:
M = ((3 - 5)/2, (2 + 6)/2)
Now, just solve it down to get M = (-1,4).

The midpoint of the segment with endpoints A(-5,6) and B (3,2) is (-1,4). Hope this helps ALot and have a wonderful day!
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Step by step explanation on how to solve -22-(6)(-9)/3
timofeeve [1]

Answer:

-4

Step-by-step explanation:

-22-(6)(-9)/3

my bad it shows explanation

5 0
3 years ago
Read 2 more answers
Im not sure how to solve this problem in Algebra<br><br> 6z=4(1/2z-8)
Blizzard [7]

Z = -2

I hope this helps

3 0
3 years ago
A baseball is hit with an initial upward velocity of 70 feet per second from a height of 4 feet above the ground. The equation h
Katyanochek1 [597]
To solve you need to set the equation equal to 6 (the height at which the player caught the ball.

6 = -16t^2 + 70t + 4

Next put the equation in standard form by subtracting 6 from both sides

-16t^2 + 70t - 2 = 0

This equation can be simplified by dividing by 2

-8t^2 + 35t - 1 = 0

This equation cannot be factored, but we can use the quadratic formula to find a value for x. Using the equation above we can find the values for a=-8, b = 35 and c = -1.

using the quadratic formula we can solve for x

-b +/- sqrt(b^2 - 4ac)
-------------------------------
       2a

The solutions are

0.03 and 4.35. as 0.03 seems an unrealistic time to hit and catch a baseball we would expect the time to be 4.35 seconds.
8 0
3 years ago
If 3 3/4 lb. of candy cost $20.25 how much world 1 lb. of candy cost?
Maru [420]

$ 20.25 divided by 3 3/4 lbs

change 3 3/4 to a decimal  = 3.75

$20.25 / 3.75 lbs

$5.40 per pound

so 1 pound of candy costs $5.40

Answer: $5.40

3 0
3 years ago
How do I solve this
Sladkaya [172]

Step-by-step explanation:

\bf \underline{Solution-} \\

\textsf{Given,}\\

\sf{ \frac{ {a}^{6} {b}^{4}  }{ {a}^{2} {b}^{3}  } } \\

\textsf{Using law of intergal expo.. aᵐ ÷ aⁿ = aᵐ - ⁿ}\\

\sf{ \Rightarrow \:  {a}^{(6 - 2)}  {b}^{(4 - 3)} } \\

\sf{ \Rightarrow \:  {a}^{4}  {b}^{1} } \\

\sf{ \Rightarrow \:  {a}^{4}  {b}^{} } \\

\bf \underline{Hope\: this\: helps.} \\

4 0
2 years ago
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