Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Answer:
Answers are below
Step-by-step explanation:
Hour 0 1 bacterium
Hour 1 3 bacterium
Hour 2 9 bacterium
Hour 3 27 bacterium
Hour 4 81 bacterium
Hour 5 243 bacterium
Hour 6 729 bacterium
After 24 hours, the number of the bacterium will reach 282,429,536,481.
B) This table represents exponential growth because of the number of bacterium always being multiplied by 3.
C) The reason that any number to the zero power is one is that any number to the zero power is just the product of no numbers at all, which is the multiplicative identity, 1.
D) Y = 1 + 3 to the power of x
E) The rule would change by having all of the numbers multiplied by 100 since there is 100 bacterium at Hour 0.
Answer:
D
C
Nameric Response
a
Step-by-step explanation:
a rectangular tabletop has diagonal
Answer: 4.5%
Step-by-step explanation:
Percentage will be calculated as:
No of players with height below 74/ total number of players x 100
From the question, Only one player has height of below 74
Total number of heights recorded is from 22 players
% = 1/22 × 100
0.04545 x 100
= 4.5%
I hope this helps.
The answer for this problem would be : true