Answer:
SAS theorem
Step-by-step explanation:
Given
Required
Which theorem shows △ABE ≅ △CDE.
From the question, we understand that:
AC and BD intersects at E.
This implies that:
and
So, the congruent sides and angles of △ABE and △CDE are:
---- S
---- A
or --- S
<em>Hence, the theorem that compares both triangles is the SAS theorem</em>
Answer:
25
Step-by-step explanation:
When we write expressions for the total cost of each field visit and set them equal, we find the solution to be the ratio of the difference in fixed cost to the difference in variable cost.
y = 75 +7x . . . . . cost for x students to visit the science center
y = 50 +8x . . . . cost for x students to visit the natural history museum
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Subtracting the first equation from the second, we get ...
0 = -25 +x
25 = x . . . . . add 25; the number of students such that costs are equal
The cost will be the same either place for 25 students.
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<em>Additional comment</em>
Here, the fixed cost difference is 75-50=25, and the variable cost difference is 8-7=1. The ratio of these costs is ...
$25/($1 /student) = 25 students.
This relationship only holds when the higher fixed cost is associated with the lower variable cost. Charges are such that one place caters to larger numbers of students (science center), and one prefers fewer students (natural history museum).
Answer:
6 (19 x - 2)
Step-by-step explanation:
Simplify the following:
6 - 3 (4 - 3 x) - 3 x - 6×9 x + 18×9 x - 6
-6×9 = -54:
6 - 3 (4 - 3 x) - 3 x + -54 x + 18×9 x - 6
18×9 = 162:
6 - 3 (4 - 3 x) - 3 x - 54 x + 162 x - 6
Grouping like terms, 6 - 3 (4 - 3 x) - 3 x - 54 x + 162 x - 6 = (-3 x - 54 x + 162 x) - 3 (4 - 3 x) + (6 - 6):
(-3 x - 54 x + 162 x) - 3 (4 - 3 x) + (6 - 6)
-3 x - 54 x + 162 x = 105 x:
105 x - 3 (4 - 3 x) + (6 - 6)
6 - 6 = 0:
105 x - 3 (4 - 3 x)
-3 (4 - 3 x) = 9 x - 12:
9 x - 12 + 105 x
Grouping like terms, 105 x + 9 x - 12 = (105 x + 9 x) - 12:
(105 x + 9 x) - 12
105 x + 9 x = 114 x:
114 x - 12
Factor 6 out of 114 x - 12:
Answer: 6 (19 x - 2)
Answer: a) 1 / ⁴⁰C₅ b) 0.33
Step-by-step explanation:
a) The sample space consists of all numbers 1-40.
Since any of the number can be taken from the sample space so each of five 5 distinct numbers we take has equal probability of occurring. So probability of each 5 numbers set we take will be equal to 1 / ⁴⁰C₅
b)
If we pick exactly 3 even number then that means other 2 will be odd.
So, we have sample space of 40 numbers out of which 20 are even and 20 are odd.
Now we have to pick 3 even out of 20 and 2 odd out of 20.
Probability = ²⁰C₃ * ²⁰C₂ / ⁴⁰C₅
Probability= 0.33
percent discount = (discount)/ original * 100
= (20)/250 * 100
=.08*100
= 8 percent
He got an 8 percent discount
