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Sphinxa [80]
4 years ago
8

You will get 16 points if you slove this correctly

Mathematics
1 answer:
Hitman42 [59]4 years ago
8 0
M1 = Fd²/Gm2. ................................
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What are the x-intercepts of the graph of f(x) = (2x-1)(2x-5)? Show your work.
nlexa [21]

Answer:

Step-by-step explanation:

The x intercepts are obtained by equating the factors to zero.

2x - 1 = 0

2x = 1

x = 1/2

2x - 5 = 0

2x = 5

x = 5/2

x = 2 1/2 or 2.5

The graph of f(x) = (2x -1)*(2x - 5) is given below. The x intercepts are labeled.

4 0
3 years ago
Suppose query Q1 obtains the median ml of a set S1 of values, and query Q2 obtains the median m2 of a subset S2 of S1. If m1 2,
kari74 [83]

Answer/explanation:

Suppose S1 is the number of patients above 35years receiving medical treatment, and S2 is the number of patients below 35 years receiving medical.

then, S1 not in S2 simply means patients that are not receiving medical treatment.

And If M1 < M2, it means a lower number of patients above 35years than the patients below 35years receive medical treatment.

8 0
3 years ago
The function f(x)=5(2)^x was replaced with f(x)+k , resulting in the function graphed below.
ella [17]
In this problem, you have to find the y- intercept of f(x)=5(2)^x. I graphed mine into a graphing calculator. An algebraic way to find it is to input x=0 in the function. The y-intercept is 5.  You can see the y-intercept for the new one is -2. That means we shifted the graph down 7 units. (Vertical Shift down 7)  
k=-7
5 0
3 years ago
Read 2 more answers
On a very cold morning it was -7 Fahrenheit as the day went on the temperature rose 3° each hour which equation shows the temper
tiny-mole [99]

Answer:

T = -7 + 3t .

Step-by-step explanation:

T = -7 + 3t   where T = the temperature and t = the times in hours.

5 0
3 years ago
Read 2 more answers
Identify the best big-O estimate for the number of comparisons used by the algorithm that determines the number of 1s in a bit s
Westkost [7]

Answer:

0(n)

Step-by-step explanation:

Result previous exercise:  

procedure count(a1a2...an : string with n > 1)

i:=0

for k:=1 to n

if ak =1 then i:=i + I

return i  

<em>Note</em><em>: If you use a different algorithm, then you could possible get different results.  </em>

<u>SOLUTION  </u>

There is only one part of the code that contains an operation (comparison), namely if a_k =1  

This comparison is executed in every iteration of the for-loop  

k can take on the values from 1 to n (for k:=I to n), thus k can take on n values.  

Thus in total there are then n comparisons, while n is 0(n).

5 0
3 years ago
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