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Effectus [21]
3 years ago
7

Find the explicit rule for arithmetic sequence 13, 23, 33, 43

Mathematics
2 answers:
marta [7]3 years ago
5 0

Answer:  i forgot what the sequence is called but it is that sequence where you where subtract the first two numbers so for example if you subtract 13 from 23 you would get ten then you go to the next set of numbers so then you would subtract 33 from 43 and get 10..

Step-by-step explanation:

23-13=10, 43-33=10, 53-43=10, 63-53=10 and so on

so this sequence is having you find the common difference

hope this helps

LuckyWell [14K]3 years ago
4 0

Answer:

Add 10 to get the next term

Step-by-step explanation:

13

13 + 10 = 23

23 + 10 = 33

33 + 10 = 43

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sergeinik [125]

Answer:

$28

Step-by-step explanation:

You subtract $44 from $100 since that is the cast of the jeans. Then get left remaining with $56. Since he wants to buy 2 shirts only you divide 56 by 2 to then equaling $28. So then each shirt is $28.

5 0
3 years ago
What is The factor to this problem?
kodGreya [7K]
D is the correct answer
7 0
3 years ago
What’s the answer 6x=4x+140
dmitriy555 [2]
1) given 6x = 4x + 140

2) subtract 4x from both sides => 6x - 4x = 4x - 4x + 140

=> 2x = 140

3) divide both members by 2 => 2x / 2 = 140 / 2

=> x = 70

4) Answer: x = 70
6 0
3 years ago
Read 2 more answers
Das has 3/4 of bottle of water.He drinks 3/8 of the bottle.How much of the bottle dose he have left?
sesenic [268]

Answer:

3/8

Step-by-step explanation

Convert 3/4 to 6/8 to make it easier subract since this problem asks how much he has left.

So 6/8-3/8=3/8

4 0
3 years ago
The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

Simplify:

\frac{1}{5} = e^{-0.1386t}

Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

 [using value of \log_e (0.2) = -1.6094379124341 ]

then;

t = \frac{-1.6094379124341}{-0.1386}

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams


6 0
2 years ago
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