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Maksim231197 [3]
3 years ago
11

What is the product?

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
7 0
Hey there!

In order to solve this problem, you'll look at (x⁴)(3x³ – 2) first. You need to multiply 4x by both numbers in the binomial to get the distributed version that you'll use later on. 

(x⁴)(3x³) = 3x⁷
(x⁴)(–2) = –2x⁴

Now, your problem is (3x⁷ – 2x⁴)(4x² <span>+ 5x). You will complete the distributing by multiplying the first term of the first binomial by both terms of the second binomial, then repeating this with the second term. You'll then want to add or subtract any repeated terms to combine them, if applicable. Remember that to multiply exponents together, all you need to do is add the numbers. x is the same as x</span>¹.<span>

</span>(3x⁷)(4x²) = 12x⁹
(3x⁷)(5x) = 15x⁸
(–2x⁴)(4x²) = –8x⁶
(–2x⁴)(5x) = –10x⁵

So, your final expanded product will be (12x⁹ + 15x⁸ – 8x⁶ – 10x⁵). Your answer should be letter A. Hope this helped you out! :-)
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Simplify and evaluate<br><br> (6)(2^3)^2 / (2^2)^2
sveticcg [70]

Simplify and evaluate

(6)(2^3)^2 = 384

(2^2)^2 = 16

5 0
3 years ago
Which equation DOES NOT represent the problem?
LUCKY_DIMON [66]

the last option

42t=28t+0.25


hope this helps

<3

6 0
3 years ago
What is the slope of the line that passes through the points (4,9) and (6,10)
max2010maxim [7]

Answer: 2

Step-by-step explanation:

4 0
3 years ago
Please help show work too please thank you
Black_prince [1.1K]
(3x-9) +(x+19)+x=180
5x+10=180
-10=-10
5x=170
5 = 5
x=34

2x+(2x+10)+x=180
5x+10=180
-10=-10
5x=170
5 = 5
x=34

yes they are similar
6 0
3 years ago
What are the solutions to the following system?
bija089 [108]

The solutions are (\sqrt{2},-1) \text { and }(-\sqrt{2},-1).

Solution:

Given equation:

-2 x^{2}+y=-5

Add 2 x^{2} on both sides.

-2 x^{2}+y+2 x^{2}=-5+2 x^{2}

y=-5+2 x^{2} -------- (1)

y=-3 x^{2}+5 (given)  -------- (2)

Equate (1) and (2).

-5+2 x^{2}=-3 x^{2}+5

Add 3 x^{2} on both sides.

-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}

-5+5x^{2}=5

Add 5 on both sides.

-5+5x^{2}+5=5+5

5x^{2}=10

Divide by 5 on both sides, we get

x^{2}=2

Taking square root on both sides, we get

x=\sqrt{2}, x=-\sqrt{2}

Substitute x=\sqrt{2} in (1).

y=-5+2(\sqrt{2})^2

y=-5+4

y=-1

Substitute x=-\sqrt{2} in (1).

y=-5+2(-\sqrt{2})^2

y=-5+4

y=-1

Therefore the solutions are (\sqrt{2},-1) \text { and }(-\sqrt{2},-1).

Option C is the correct answer.

6 0
3 years ago
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