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RideAnS [48]
3 years ago
14

Four times the cube of a number is less than the difference between forty and the number. Select the inequality that represents

this relationship.
(4x)3 < 40 - x

4x3 < x - 40

(4x)3 < x - 40

4x3 < 40 - x
Mathematics
2 answers:
dsp733 years ago
7 0

Answer:

Step-by-step explanation:

let the number be x, now we are given that four times the cube of a number which means four multiplied by the cube of number

i.e 4 multiplied by  is less than the difference of 40 and the number x i.e 40 - x

x is for sure less than 40 as  is less than the difference between 40 and x so if we write x - 40 then we will obtain negative value which will be greater than .

tigry1 [53]3 years ago
6 0

<u>Answer:</u>

4x^3 < 40 - x

<u>Explanation:</u>

let the number be x, now we are given that four times the cube of a number which means four multiplied by the cube of number

i.e 4 multiplied by x^3 is less than the difference of 40 and the number x i.e 40 - x

x is for sure less than 40 as x^3 is less than the difference between 40 and x so if we write x - 40 then we will obtain negative value which will be greater than x^3.

So, the inequality obtained can be written as 4x^3 < 40 - x

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3 years ago
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8 0
2 years ago
Read 2 more answers
if you have 89 apples and you take 72 away and buy 14 more and take 12 away then buy 42 more and give them 16 more
Delicious77 [7]

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Step-by-step explanation:

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5 0
3 years ago
Divide x4+2x2−24<br> by x+2
Ipatiy [6.2K]

\begin{array}{c|c}_{-}\ x^4+2x^2-24 &\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\! \underline{  x+2  } \\ \!\!\!\!\!\!\!\!\!\!\! \underline{x^4+2x^3}& x^3-2x^2+4x-8  \\{ \big{_{-}}}-2x^3-24& \\\underline{-2x^3-4x^2}& \\  _{-} \ 4x^2-24 & \\ \underline{4x^2+8x}&   \\  _{-}-8x-24& \\ \underline{-8x-16} & \\ -8 &\end {array }

\displaystyle \frac{x^4+2x^2-24}{x+2} =x^3-2x^2+4x-8 -\frac{8}{x+2}

7 0
2 years ago
Read 2 more answers
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