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RideAnS [48]
3 years ago
14

Four times the cube of a number is less than the difference between forty and the number. Select the inequality that represents

this relationship.
(4x)3 < 40 - x

4x3 < x - 40

(4x)3 < x - 40

4x3 < 40 - x
Mathematics
2 answers:
dsp733 years ago
7 0

Answer:

Step-by-step explanation:

let the number be x, now we are given that four times the cube of a number which means four multiplied by the cube of number

i.e 4 multiplied by  is less than the difference of 40 and the number x i.e 40 - x

x is for sure less than 40 as  is less than the difference between 40 and x so if we write x - 40 then we will obtain negative value which will be greater than .

tigry1 [53]3 years ago
6 0

<u>Answer:</u>

4x^3 < 40 - x

<u>Explanation:</u>

let the number be x, now we are given that four times the cube of a number which means four multiplied by the cube of number

i.e 4 multiplied by x^3 is less than the difference of 40 and the number x i.e 40 - x

x is for sure less than 40 as x^3 is less than the difference between 40 and x so if we write x - 40 then we will obtain negative value which will be greater than x^3.

So, the inequality obtained can be written as 4x^3 < 40 - x

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Factor completely 2x3 + 8x2 + 3x + 12.
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Answer:

(2x^2+3)(x+4).

Step-by-step explanation:

2x^3+8x^2+3x+12

We need to find the factors of given equation;

Solution:

On Solving the above equation we get;

Now First we will take common factor from first 2 terms which is 2x^2 we get;

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Now we will take the common factor from the last 2 terms which is 3 we get;

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3 years ago
Which equation demonstrates the additive identity property?
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Answer:

Step-by-step explanation:

Solve for o in the equation (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 41o(7 + 4)(1) = 7 + 41o(7 + 41) + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 41o(7 + 4): Distribute the 41o to each term in (7+4)

41o * 7 = (41 * 7)o = 287o 41o * 4 = (41 * 4)o = 164o

Our Total expanded term is 287o + 164o

Simplify 41o(7 + 41): Distribute the 41o to each term in (7+41)

41o * 7 = (41 * 7)o = 287o 41o * 41 = (41 * 41)o = 1681o

Our Total expanded term is 287o + 1681o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o(1) = 7 + 287o + 1681o + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 164o(1): Distribute the 164o to each term in (1)

164o * 1 = (164 * 1)o = 164o Our Total expanded term is 164o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o = 7 + 287o + 1681o + ( - 7 - 41) = 0

Step 1: Group variables: We need to group our variables (7 and 14©(7. To do that, we subtract 14©(7 from both sides (7 - 14©(7 = 14©(7 - 14©(7

Step 2: Cancel 14©(7 on the right side: 0o = 0 Step 3: Divide each side of the equation by 0

0o 0 = 0 0 o =

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