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postnew [5]
3 years ago
14

The sides of a right triangle consist of two legs and a hypotenuse. If the two legs of a right triangle each have a length of 26

centimeters and the hypotenuse has a length of 57 millimeters, what is the perimeter of the triangle? *
Mathematics
2 answers:
Ksju [112]3 years ago
7 0
<span>The sides of a right triangle consist of two legs and a hypotenuse. If the two legs of a right triangle each have a length of 26 centimeters and the hypotenuse has a length of 57 millimeters, what is the perimeter of the triangle.
</span>
Vikki [24]3 years ago
5 0
The sides of a right triangle consist of two legs and a hypotenuse. If the two legs of a right triangle each have a length of 26 centimeters and the hypotenuse has a length of 57 millimeters, what is the perimeter of the triangle? *A) 31.7 mmB) 83 mmC) 317 mm<span>D) 830 mm</span>
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Answer: B. 53

Step-by-step explanation:

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3 years ago
Which of the following expressions are factors of 25x^3−75x^2−9x+27?
Natali [406]

Answer:

I am not sure but I think the correct answer is c

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3 years ago
A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f
zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time t

At t=0, the weight of the bucket is 6+36=42 \mathrm{lb}

After t seconds, the weight of the bucket is 42-0.15 t \mathrm{lb}

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after t seconds is x=1.5 t

Since the well is 80 ft deep, the time to pull out the bucket is \frac{80}{2}=40 \mathrm{~s}

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

W=\int_{t=0}^{t=36} F d x

Use x=1.5 t and F=42-0.15 t

W=\int_{0}^{36}(42-0.15 t)(1.5 d t)

=\int_{0}^{36} 63-0.225 t d t

=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}

=\left[63 t-0.2 t^{2}\right]_{0}^{36}

W=3200 \mathrm{ft} \cdot \mathrm{lb}

4 0
3 years ago
Your friend has $90 when he goes to the fair. He spends $5 to enter the fair and $15 on food. Rides at the fair cost $1.50 per r
ra1l [238]

Answer:

-1.5x + 70

Step-by-step explanation:

Total money he takes while going to the fair = $90

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Total he spent now is given by

Now, he spend on rides at the fair i.e. 1.50 per ride .

Let the number of rides be x

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So, the spending money can be expressed as

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So it becomes

f(x) = 70 - 1.50x

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3 years ago
Is the height of these students a function of their wrist circumference?
statuscvo [17]

Answer:

no

Step-by-step explanation:

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