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postnew [5]
3 years ago
14

The sides of a right triangle consist of two legs and a hypotenuse. If the two legs of a right triangle each have a length of 26

centimeters and the hypotenuse has a length of 57 millimeters, what is the perimeter of the triangle? *
Mathematics
2 answers:
Ksju [112]3 years ago
7 0
<span>The sides of a right triangle consist of two legs and a hypotenuse. If the two legs of a right triangle each have a length of 26 centimeters and the hypotenuse has a length of 57 millimeters, what is the perimeter of the triangle.
</span>
Vikki [24]3 years ago
5 0
The sides of a right triangle consist of two legs and a hypotenuse. If the two legs of a right triangle each have a length of 26 centimeters and the hypotenuse has a length of 57 millimeters, what is the perimeter of the triangle? *A) 31.7 mmB) 83 mmC) 317 mm<span>D) 830 mm</span>
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Which statement is correct?
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hbw ygav

Step-by-step explanation:

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3 years ago
Selena earned $200 last month babysitting. She used 25 of her earnings to buy a video game. How much did she spend on the video
babymother [125]

Answer:

See below

Step-by-step explanation:

<u>Is that $25 or 35%?</u>

If $25, she spent $25.

If 25%, she spent (0.25)*(200) = $50.

3 0
2 years ago
An ice-skating competition lasted three days. Day one had an attendance of 16,390 people. Day two had an attendance of 16,550 pe
lana [24]

Answer:

Day\ 3 = 16237

Day\ 1 = 16390

Day\ 2 = 16550

Step-by-step explanation:

Given

Day\ 1 = 16390

Day\ 2 = 16550

Day\ 3 = 16237

Required

Order from least to greatest

Comparing 16390, 16550 and 16237.

The order of arrangement from least to greatest is:

16327, 16390 and 16550.

So, we have:

Day\ 3 = 16237

Day\ 1 = 16390

Day\ 2 = 16550

6 0
3 years ago
Consider the following quadratic equation x^2 =4x -5. How many solutions does it have?
aleksandrvk [35]
The answer for your question is C.
5 0
3 years ago
Read 2 more answers
Please find which quadratic equation matches the graph with work attached
lesya [120]

Answer:

C

Step-by-step explanation:

Firstly, we know that the function must be negative due to its shape. This means that the answer cannot be B

Next we can use the equation x=\frac{-b}{2a} that is used in order to find the vertex of the parabola.

A)

f(x)=-x^2+6x+7\\a=-1,b=6,c=7\\\\x=\frac{-6}{-2} \\x=3

As the vertex is at x=3 on the graph, this one could be a contender.

C)

f(x)=-x^2+6x-7\\a=-1,b=6, c=-7\\\\x=\frac{-6}{-2} \\\\x=3

This also could be the equation

D)

f(x)=-x^2-6x-7\\\\a=-1, b=-6, c=-7\\\\x=\frac{6}{-2} \\\\x=-3

This rules option D out.

For this last step, we can look at where the zeroes would be for each equation. (These values are irrational, so we cannot look at specific number)

A)

f(x)=-(x^2-6x-7)

As this equation has a negative value for c, this means that one zero must be positive and the other must be negative.

This means that option A can be ruled out

C)

f(x)=-(x^2-6x+7)

As this equation has a positive value for c, this means that both of the zeroes must be positive. This means that it is the only one that fits all of the criteria.

7 0
3 years ago
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