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3 years ago

Part A please. Possibly giving brainliest to the one who answers the question

Mathematics

1 answer:

lara [203]3 years ago

8 0

Step-by-step explanation:

Answer: 16 and 5/4 tbsp of sugar.

7 ÷ 2 = 3.5

Don't worry about the decimal for now, just find how many tbsp of sugar she needs for 6 tbsp of milk.

6 ÷ 2 = 3

3 x 5 = 15

Now, we will focus in the 0.5 tbsp of milk.

Find how much 1/2 a tbsp of milk can get for sugar.

4 1/2 tbsp of milk is 5 tbsp of sugar.

5 ÷ 4 = 1.25

So 16 and 5/4 tbsp of sugar is required.

(Answer for Part A)

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A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0

3 years ago

A recipe calls for 5.0 qt of milk. what is this quantity in cubic centimeters?

Ede4ka [16]

To answer this question, you need to understand how to convert unit. In this case, it will be quarts(qt) into centimeter cubic(cm3). A quart is 1/4 gallon and one gallon equal to <span>3 785.4 cm3. Then the calculation would be:
5qt of milk * 0.25 gallon/qt * </span>3 785.4 cm3/gallon= 4731.75 cm3

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2 years ago

Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack

Rainbow [258]

Answer:

Step-by-step explanation:

Given the question :

Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack bags should be identified without any food leftover, what is the greatest number of snack bags Serena can make?

Number of granolas = 6

Number of dried fruits = 10

Since the snackbag is to be designed in such a way that there should be no food leftover, the greatest number of snack bags Serena can make could be obtained by getting the highest common factor of (6 and 10)

____6____10

2___3____5

Here, the highest common factor of 6 and 10 is 2

Hence, the greatest number of snack bags she can make is 2.

5 0

2 years ago

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maria [59]

Answer:

(-2,6)

Step-by-step explanation:

8 0

2 years ago

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Determine whether the two expressions are equivalent. If so, tell what property is applied.

Hoochie [10]

Answer:

I think its associative property but I am not sure.

Step-by-step explanation:

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3 years ago