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labwork [276]
3 years ago
8

The slope f′(x) at each point (x,y) on a curve y=f(x) is given, along with a point (a,b) on the curve. Use this information to f

ind f(x). f′(x) = 4x/(1 + 7x^2) (0,10) NOTE: OF absolute value symbols, | | , are needed for the answer, then use abs(expression). For example, ln|x| must be entered as ln(abs(x))
Mathematics
1 answer:
Montano1993 [528]3 years ago
7 0

f'(x)=\dfrac{4x}{1+7x^2}

Integrating gives

f(x)=\displaystyle\int\frac{4x}{1+7x^2}\,\mathrm dx

To compute the integral, substitute u=1+7x^2, so that \frac27\,\mathrm du=4x\,\mathrm dx. Then

f(x)=\displaystyle\frac27\int\frac{\mathrm du}u=\frac27\ln|u|+C

Since u=1+7x^2>0 for all x, we can drop the absolute value, so we end up with

f(x)=\dfrac27\ln(1+7x^2)+C

Given that f(0)=10, we have

10=\dfrac27\ln1+C\implies C=10

so that

\boxed{f(x)=\dfrac27\ln(1+7x^2)+10}

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You can find the slope with this following equation: (y(2)-y(1))/(x(2)-x(1))

In this case the points are (0,4) and (-2,-3). The first set being (0,4) and the second (-2,-3). This means (0,4) can be expressed as (x(1),y(1)) and (-2,-3) expressed as (x(2),y(2)). Plugging these numbers into the slope equation gives us: (-3-4)/(-2-0) = -7/-2 = 7/2.

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We are give a set of points which it passes through, we can simply plug them in:

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We get 4 = 0 +b .... 4=b

our final equation is : y=(7/2)x+4

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