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jeyben [28]
3 years ago
12

Test the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test. Upper H 0​: pequals0.6 versus U

pper H 1​: pgreater than0.6 nequals200​; xequals135​, alphaequals0.05 Is np 0 (1 minus p 0 )greater than or equals​10.
Use technology to find the P-Value.
Mathematics
1 answer:
kow [346]3 years ago
7 0

Answer:

Step-by-step explanation:

From the given information:

The null and the alternative hypothesis can be well written as:

H_o:P=0.6

H_1:P>0.6

Given that:

n = 200

x = 135

Alpha ∝ = 0.05 level of significance

Then;

⇒ n \times p\times (1-P)

= 200 × 0.6 × (1 -0.6)

= 200 × 0.6 × 0.4

= 48 ≥ 10

The sample proportion \hat P = \dfrac{x}{n}

= \dfrac{135}{200}

= 0.675

The test statistics Z = \dfrac{\hat P - P}{\sqrt{ \dfrac{P(1-P)}{n} }}

Z = \dfrac{0.675 - 0.6}{\sqrt{ \dfrac{0.6 \times 0.4}{200} }}

Z = \dfrac{0.075}{\sqrt{ \dfrac{0.24}{200} }}

Z = 2.165

The P-value = P(Z > 2.165)

= 1 - P(Z < 2.165)

From the z tables

= 1 - 0.9848

= 0.0152

Reject the null hypothesis since P-Value is lesser than alpha. ( i.e. 0.0152 < 0.05).

Thus, there is enough evidence to conclude that the value of the population proportion is greater than 0.6

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