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Kruka [31]
4 years ago
13

Can someone PLEASE help me with questions #5 and 6

Mathematics
1 answer:
Hatshy [7]4 years ago
5 0

Domain={8,9}

Range = { -3,-4,-6,-9}

No relation is not function as elements in domain are related to more than one element of codomain

You might be interested in
19=h/3 -8 whats h??
creativ13 [48]
First add the 8 to both sides, canceling out the 8 in the right and adding it to the 19 on the left, making it 27. Multiplying undoes division so, After that, multiply by three on both sides, canceling out the three on the right and multiply 27 by 3, making it 81.

8 0
3 years ago
The lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of
valina [46]

Answer:

(221.39, 300.61) and (255.2223, 266.7777)

Step-by-step explanation:

Given that X, the  lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of 17 days

Middle 98% would lie on either side of the mean with probability ±2.33 in the std normal distribution on either side of 0

Corresponding we have x scores as

Between 261-2.33*17 and 261+2.33*17

i.e. in the interval = (221.39, 300.61)

If sample size = 47, then std error of sample would be

\frac{17}{\sqrt{47} }

So 98% of pregnancies would lie between

261-2.33*\frac{17}{\sqrt{47} } and 262+2.33*\frac{17}{\sqrt{47} }

= (255.2223, 266.7777)

8 0
3 years ago
I have an F I need help
Vikentia [17]

Answer:

I think it's B

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
5 3/12 - 1 4/9 what is the answer
Vlad1618 [11]

The answer is 3 29/36

5 3/12 = 5 9/36

1  4/9 = 1 16/36

So the answer equation is 5 9/36 - 1 16/36

                                      down: 4 45/36 - 1 16/36 = 3 29/36

I HOPE THIS HELPS

3 0
4 years ago
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
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