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Fed [463]
3 years ago
7

 The price of Stock A at 9 A.M. was ​$14.15. Since​ then, the price has been increasing at the rate of ​$0.06 each hour. At noon

the price of Stock B was ​$14.65. It begins to decrease at the rate of ​$0.08 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?
Mathematics
1 answer:
Marina86 [1]3 years ago
3 0

Answer:

<h2>2 hours</h2>

Step-by-step explanation:

Easiest way to solve this is add and subtract till we get the values balanced.

Stock A

9 am $14.15

10 am $14.21

11 am $14.27

12 pm $14.33

1 pm $14.39

2 pm $14.45

Stock B

12 pm $14.65

1 pm $14.57

2 pm $14.45

Notice the bold values are the same at the same time 2 pm. If we start at 12 pm with stock B, it will be 2 hours before the prices are the same.

I'm always happy to help :)

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Need help ASAP !!! And show work please
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Answer:

\sqrt{40} or 6.32

Step-by-step explanation:

We can find the distance between two points by using this formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

where the x and y values are derived from the given points

The points given are ( -2 , 5 ) and ( 4 , 3 )

So we plug in the x and y values of those coordinates into the distance formula

\sqrt{(4-(-2)^2+(3-5)^2} \\4-(-2)=6\\3-5=-2\\d=\sqrt{6^2+-2^2} \\6^2=36\\-2^2=4\\36+4=40\\d=\sqrt{40}

or 6.32

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