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Fed [463]
3 years ago
7

 The price of Stock A at 9 A.M. was ​$14.15. Since​ then, the price has been increasing at the rate of ​$0.06 each hour. At noon

the price of Stock B was ​$14.65. It begins to decrease at the rate of ​$0.08 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?
Mathematics
1 answer:
Marina86 [1]3 years ago
3 0

Answer:

<h2>2 hours</h2>

Step-by-step explanation:

Easiest way to solve this is add and subtract till we get the values balanced.

Stock A

9 am $14.15

10 am $14.21

11 am $14.27

12 pm $14.33

1 pm $14.39

2 pm $14.45

Stock B

12 pm $14.65

1 pm $14.57

2 pm $14.45

Notice the bold values are the same at the same time 2 pm. If we start at 12 pm with stock B, it will be 2 hours before the prices are the same.

I'm always happy to help :)

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Answer:

Option B 1/64

Step-by-step explanation:

\frac{4^{-\frac{11}{3} } }{4^{-\frac{2}{3} } } =4^{-11/3+2/3} =4^{-9/3} =4^{-3} =\frac{1}{4^{3} }=\frac{1}{64}

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3 years ago
Wendy is creating a large soup based on a recipe. Her recipe calls for of a pint of milk, but she only has of a pint of milk, so
xeze [42]

Answer:

She can only make 5/6 of her recipe with the amount of milk that she has.

Step-by-step explanation:

Some data of this problem is missing, the data missing is:

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Now, to know what's the portion she can do with that amount we need to divide the amount of milk she has by the total amount she needs:

\frac{5}{8} ÷\frac{3}{4}

When we divide we turn the second fraction upside down (the numerator becomes the denominator and viceversa) and multiply, thus:

\frac{5}{8}÷\frac{3}{4}=\frac{5}{8}×\frac{4}{3} =\frac{20}{24}

If we simplify this last expression we have:

\frac{20}{24}=\frac{10}{12}  =\frac{5}{6}

Thus, she can only make 5/6 of her recipe with the amount of milk that she has.

<em>Note: In case the data missing is different, you can apply this same procedure with the fractions you have. </em>

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