P = 300/V
Because in order to isolate P, you have to divide V on both sides.
300 feet you add 90 twice which gets you 180 and then add 60 twice which gets you 120 and 120 plus 180 is 300
4/4=1. So we need to subtract 1 from 4 to get the final Answer which is 3.
Answer:
2.28% probability that a person selected at random will have an IQ of 110 or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a person selected at random will have an IQ of 110 or higher?
This is 1 subtracted by the pvalue of Z when X = 110. So
has a pvalue of 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or higher
You have to combine like numbers
y-4x-1(1-6x)+3y+x
4y -4x-(1-6x)+x
4y - 4x - 1 + 6x + x
4y + 3x - 1