I’m pretty sure the first one is 4 & the second one is 6; if that’s what you’re asking.
Answer:
<h2><em>
50.42m/s</em></h2>
Step-by-step explanation:
Average speed is the change in distance of a body with respect to time. This is expressed as:

Given the function of the height in metres expressed as y = 56t − 1.86t² and time interval [1,2]
t₁ = 1sec and t₂ = 2 secs
y(t₂) = 56t₂ − 1.86t₂²
y(2) = 56(2) − 1.86(2)²
y(2) = 112-7.44
y(2) = 104.56
y(t₁ ) = 56t₁ − 1.86t₁ ²
y(1) = 56(1) − 1.86(1)²
y(1) = 56-1.86
y(1) = 54.14
Substituting the derived value into the formula for finding the average speed:

<em>Hence, the average speed over the given time intervals. [1, 2] is 50.42m/s</em>
2 out of 6 times or 1 out of 3 times. It is most likely to land on a 2 than the other numbers.
(5.15 pound) x (3.40 buck/pound) = <em>17.51 buck</em>