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2 years ago

If your correct i will give u brainlist :)))))))))))

Mathematics

1 answer:

TiliK225 [7]2 years ago

7 0

Answer:

This is not the answer this is the trick to find it

Step-by-step explanation:

The points after reflection will follow points equal but different direction, to the path followed before the reflection. So, if the line would cover 3.5 on the x and 5 on the y; it will reflect symmetrically giving you the formula to get your answer.

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Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago

Determine the inverse of a function. please help!

Brums [2.3K]

This is what i got!!

8 0

3 years ago

How long does it take to double a $1,000 investment that pays 6.5% annual interest, compounded monthly?

ahrayia [7]

2p=p(1+0.065/12)^12t
2=(1+0.065/12)^12t
Solve for t
T= [log(2)/ log(1+0.065/12)] /12
T= 10.7 years or if you want to round it would be 11

Answer: 10.7 years or 11 years

Answer: You can use the compound interest formula: A=P(1+interest)^n

A=the new capital
P=the capital invested
n= the #of monthly

Hope this helps (:

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3 years ago

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Graph the linear function r(x)=2

wlad13 [49]

It's a linear function with a slope 0.

It's a horizontal line (look at the picture).

4 0

3 years ago

Liza opens a new savings account. Assuming she deposits $15 every week, which equation represents the balance, y, of the savings

fiasKO [112]

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3 years ago

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