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Bas_tet [7]
3 years ago
14

The product of two numbers is 65.Their difference is 8.Find these numbers.

Mathematics
1 answer:
fgiga [73]3 years ago
5 0
15 and 5 but 8t wou”s be 7
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Help asap thank you .
frosja888 [35]

Answer:

2

Step-by-step explanation:

count up 2 count right 1, 2/1

2/1 = 2

3 0
2 years ago
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 269 day
fenix001 [56]

Answer:

a) 279 b)254

Step-by-step explanation:

Mean = 269 days

standard deviation = 8 days

let n be the pregnancy lenght.  

using normal distribution formula

z = (n – mean)/ standard deviation

n = z * standard deviation + mean

Now, z values for the top 12% has to be found using a z table.

The top 12% means 88% of area under the curve. In this case z = 1,176

n = 1,176 * 8 + 269

n = 278.4 = 279

The bottom 3% means 97% of area under the curve. In this case z = -1,882

n = -1,882 * 8 + 269

n = 253.94 = 254

6 0
3 years ago
How many days are in a month
ser-zykov [4K]
It could be 30 to 31 but February has 28 expected from a leap year with 29 days 
7 0
2 years ago
Read 2 more answers
How many numbers are equal to the sum of two odd, one-digit numbers?
Dennis_Churaev [7]

Answer:

Seven numbers.

Step-by-step explanation:

Finding the numbers, which are equal to the sum of two odd number and it has to be single digit number.

Lets look into numbers which are odd and single digit.

1 = 1+3, 1+5, 1+7, 1+9

∴ Sum of the number is 4,6,8\ and\ 10

3 = 3+5, 3+7, 3+9

∴ Sum of above number is 8,10\ and\ 12

5 = 5+7, 5+9

∴ Sum of above number is 12\ and\ 14

7= 7+9

∴ Sum of above number is 16

Now, accumlating numbers which are fullfiling the criteria, however, making sure no number should get repeated.

∴ Numbers are: 4,6,8,10,12,14\ and\ 16

Hence, there are total 7 numbers, which  are equal to the sum of two odd, one-digit numbers.

4 0
3 years ago
What is the correct factorization of 2x² + 3x - 5?
sesenic [268]
Yea it’s B because I did the mathhhhhh
4 0
2 years ago
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