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Roman55 [17]
3 years ago
6

A baker uses 2.327 kilograms of blueberries for muffins. There are four packages at the fruit market. Which amount is closest to

2.327 kilograms? A 2.3 kg B 2.42 kg © 2.33 kg 2.4 kg Iuel enrtchours the length of each Student Pencil Length (inches)
Mathematics
1 answer:
irinina [24]3 years ago
4 0

Answer:

2.33 kg

Step-by-step explanation:

If the baker needs to use 2.327 kilograms of blueberries, we are going to subtract the amount of the packages to the amount he needs and we'll see which is the smallest number.

In the case of 2.3, 2.327 - 2.3 = .027

In the case of 2.42, 2.327 - 2.42 = -0.09

In the case of 2.33, 2.327 - 2.33 = -0.003

In the case of 2.4, 2.327 - 2.4 = -0.07

Therefore, the closest amount to 2.327 is the 2.33 package.

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What is 4w + 3 = -7 equaled to
Nata [24]

Answer:


To begin solving we subtract 3 from each side

4w = -10

Next, we divide both side by 4

w = -2.5



~CoCo


5 0
3 years ago
What is the area of a regular pentagon with a side length of 9 millimeters and an apothem length of 6.2 millimeters?
Kazeer [188]
A Pentagon can be broken up into 5 equal triangles. Area of the Pentagon is the sum of all the 5 triangles.

Area of the pentagon = 5 ( 1/2 x 6.2 x 9) = 139.5 mm²

Answer: 129.5 mm² (Answer D)
5 0
3 years ago
Can someone please help me ASAP❤️
Eddi Din [679]
38,320 (for positive scientific notation you move the decimal to the right how ever many places, so move the decimal 4 places to the right in this case)
4 0
3 years ago
A sample size must be determined for estimating a population mean given that the confidence level is ​% and the desired margin o
Sauron [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

 n =290

b

 n =129

c

 The correct option is  D

Step-by-step explanation:

From the question we are told that

    The margin of error is   E  =  0.23

     The largest value is  k =  15

     The smallest value is  u = 7

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally population  standard deviation estimate is mathematically represented as

      \sigma  =  \frac{Range }{4}

Here the Range is mathematically represented as

       Range  =  k - u

=>    Range  = 15 - 7

=>    Range  = 8

=>   \sigma  =  \frac{8 }{4}

=>   \sigma  =  2

Generally the sample size is mathematically represented as

n = [\frac{Z_{\frac{\alpha }{2} } *  \sigma }{E} ] ^2

=>   n = [1.96  *  2 }{0.23} ] ^2

=>   n =290

Generally to obtain a  conservatively small sample size the population standard deviation estimate becomes

=>   \sigma  =  \frac{Range }{6}

=>   \sigma  =  \frac{8 }{6}

=>   \sigma  =1.333

Generally the conservatively small sample size is mathematically evaluated as

n = [\frac{Z_{\frac{\alpha }{2} } *  \sigma }{E} ] ^2

=>   n = [1.96  *  1.333 }{0.23} ] ^2

=>   n =129  

 

6 0
3 years ago
Organizers of an outdoor summer concert in Toronto are concerned about the weather conditions on the day of the concert. They wi
Kobotan [32]

Answer:

The value of the expected profit from the concert is 8,910

Step-by-step explanation:

Profit on a clear day X₁ = 36,000 with  13% probability.  

i.e  X₁ = 36000

    P(X₁) = 0.13

Profit on a cloudy day = 17,000 with 39% probability.

i.e  X₂ = 17000

    P(X₂) = 0.39

else,

loss of 5,000 if it rains with the probability of 48%.

i.e  X₃ = 5000

    P(X₃) = 0.48

The value of the expected profit from the concert is obtained as follows

Expected Value = (36,000*0.13) + (17,000*0.39) - (5,000*0.48)

                           = 4,680 + 6,630 - 2,400

                           = 8,910

8 0
3 years ago
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