Solution
Part 3
For this case we have 6 different terms
Part 4
We can do the following:

Part 5
And we can simplify on this way:

4/10 x 0.04 = (of means multiply)
0.4 x 0.04 =
0.016
B-8 would be the answer. This is because we are saying you have 8 less than something. So no matter what something is, we are taking away 8 from it. Since our something is unknown, we use our variable 'b' in its place, and subtract 8, giving us b-8.<span />
Answer:
or 
Step-by-step explanation:
we know that
Applying the law of cosines

In this problem we have

c is the length of the third side
Substitute




or 