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Blizzard [7]
3 years ago
14

Simplify the expression 6x+12y+5+2y+8 what is the coefficient of y and what is the constant

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
7 0
6x+12y+5+2y+8
= 6x+ (12y+2y)+ (5+8) (combine like terms)
= 6x+ 14y+ 13

Coefficient of y: 14
Constant: 13

Hope this helps~
frez [133]3 years ago
5 0
We want to find the coeficient of the y terms when added together so find all the y terms

+12y and +2y
we add them together
12y+2y=(12+2)y=(14)y=14y
coeficient is 14


the constant is the number that is set already or the number that doesn't have it multiplied by a placeholder exg. 4 is a constnat but 4x is not so find the constants
+5 and +8
we add
5+8=13
the constant is 13


y coeficient=14
constant=14
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The question is in the image below.
sineoko [7]

Answer:

The Recursive Formula for the sequence is:

\:a_n=\frac{1}{5}\left(a_{n-1}\right)     ; a₁ = 125

Hence, option D is correct.

Step-by-step explanation:

We know that a geometric sequence has a constant ratio 'r'.

The formula for the nth term of the geometric sequence is

a_n=a_1\cdot r^{n-1}

where

aₙ is the nth term of the sequence

a₁ is the first term of the sequence

r is the common ratio

We are given the explicit formula for the geometric sequence such as:

a_n=125\left(\frac{1}{5}\right)^{n-1}

comparing with the nth term of the sequence, we get

a₁ = 125

r = 1/5

Recursive Formula:

We already know that

  • a₁ = 125
  • r = 1/5

We know that each successive term in the geometric sequence is 'r' times the previous term where 'r' is the common ratio.

i.e.

a_n=ra_{n-1}

Thus, substituting r = 1/5

\:a_n=\frac{1}{5}\left(a_{n-1}\right)  

and a₁ = 125.

Therefore, the Recursive Formula for the sequence is:

\:a_n=\frac{1}{5}\left(a_{n-1}\right)     ; a₁ = 125

Hence, option D is correct.

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Answer:

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Line A is perpendicular to line B. The slope of line A is -1/9 what is the slope of line b?
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