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Sav [38]
3 years ago
5

PLEASE HELP!!!

Mathematics
1 answer:
nikitadnepr [17]3 years ago
5 0

Answer:

A) The graph shifts 5 units left and 3 units up.

Step-by-step explanation:

For a function f(x) following transformation rules is applied.

f(x-c)\rightarrow shifts function c units to the right.

f(x+c)\rightarrow shifts function c units to the right.

f(x)+b\rightarrow shifts function c units upward.

f(x)-b\rightarrow shifts function c units down upward.

Given function f(x):

f(x)=\frac{1}{x-4}+3

Function  g(x):

g(x)=\frac{1}{x+1}+6

So, to transform f(x) to g(x) we can make changes as

f(x)=\frac{1}{x-4+(5)}+3+(3)=\frac{1}{x+1}+6=g(x)

Comparing the two function we conclude the following transformation taking place:

g(x)=f(x+5)+3

From the above rule stated, we can make a statement about the transformation as following:

The graph shifts 5 units left and 3 units up.

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<em>Alternative Form: </em>3 2/3, 3.6

Step-by-step explanation:

44/12

Dive the numerator and denominator by 4

44/4 / 12/4

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PLEASE HELP<br><br>divide. (3x-2)(x-4)-(x-4)(6-5x)<br>/(4-x)(8x-1)​
8_murik_8 [283]

Answer:

x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

Step-by-step explanation:

Solve for x:

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = 0

Simplify and substitute y = 4 - x.

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = -434 + 257 (4 - x) - 37 (4 - x)^2

= -37 y^2 + 257 y - 434:

-37 y^2 + 257 y - 434 = 0

Divide both sides by -37:

y^2 - (257 y)/37 + 434/37 = 0

Subtract 434/37 from both sides:

y^2 - (257 y)/37 = -434/37

Add 66049/5476 to both sides:

y^2 - (257 y)/37 + 66049/5476 = 1817/5476

Write the left hand side as a square:

(y - 257/74)^2 = 1817/5476

Take the square root of both sides:

y - 257/74 = sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

y = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Substitute back for y = 4 - x:

4 - x = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Subtract 4 from both sides:

-x = sqrt(1817)/74 - 39/74 or y - 257/74 = -sqrt(1817)/74

Multiply both sides by -1:

x = 39/74 - sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

x = 39/74 - sqrt(1817)/74 or y = 257/74 - sqrt(1817)/74

Substitute back for y = 4 - x:

x = 39/74 - sqrt(1817)/74 or 4 - x = 257/74 - sqrt(1817)/74

Subtract 4 from both sides:

x = 39/74 - sqrt(1817)/74 or -x = -39/74 - sqrt(1817)/74

Multiply both sides by -1:

Answer:  x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

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According to the square root property, the solution set of x 2 = 25 is {±5}.<br> True<br> False
babymother [125]
I believe the correct answer is true. According to the square root property, the solution set of x^2 = 25 is {±5}. <span>The </span>square root property<span> is one method that is used to find the solutions to a quadratic (second degree) equation. This method involves taking the </span>square roots <span>of both sides of the equation. Hope this answers the question.</span>
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