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3 years ago

Solve p=10a+3b for a

Mathematics

1 answer:

Gre4nikov [31]3 years ago

5 0

Answer:

a = (p - 3b)/10

Step-by-step explanation:

Isolate the variable, a. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS (Parenthesis, Exponents (& roots), Multiplication, Division, Addition, Subtraction).

p = 10a + 3b

First, subtract 3b from both sides.

p (-3b) = 10a + 3b (-3b)

p - 3b = 10a

Next, isolate the a. Divide 10 from both sides.

(p - 3b)/10 = (10a)/10

(p - 3b)/10 = a

a = (p - 3b)/10 is your answer.

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Answer: Area of square PQRS is 81cm^2 and of ABCD is 25cm^2

You know its a square. Which means all the sides are equal and same length. If you dont know what's a square then here is the definition:

Square is a plane figure with four equal sides and four right (90°) angles.

So now we know both of are squares, in case of the first square, PQRS, one side length is already given which is PQ=9cm. Now one side is 9cm which means all the sides are 9cm's (PQ=9cm, QR=9cm, RS=9cm,SP=9cm). So to find area just multiply them:

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2 years ago

K= 1/2mv^2<br> Solve for V

jeyben [28]

Hi there!

v = ± $\sqrt{\frac{2K}{m} }$

- - - - - - - - -

K = 1/2mv²

Isolate for the variable "v". We can begin by dividing both sides by 1/2. (Multiply by the reciprocal, or 2):

2 · K = 2 · (1/2mv²)

2K = mv²

Continue isolating by dividing both sides by "m":

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