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3 years ago

Which of the following choices can be used to check the answer in this equation?

Mathematics

2 answers:

Rainbow [258]3 years ago

8 0

the answer is 110 + 95 = 205

zysi [14]3 years ago

5 0

Answer:

The answer is:

110+95=205

Step-by-step explanation:

In order to determine the answer, we have to know the useful of the equation.

In any equation, there is at least one variable. This variable may have one value, infinite values or no value to fulfil the equation.

In this case, we have a equality, where it must fulfil that the left side is equal to the right side.

To check this equality, we can choose the option:

110+95=205

This option appears when we move the value 110 to the right side, changing the sign (negativo to positive).

Finally, the right option is:

110+95=205

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Solve for y. y y —— = —— P-9 P+9

Veronika [31]

9514 1404 393

Answer:

y = 0

Step-by-step explanation:

Subtracting the right side gives ...

$\dfrac{y}{P-9}-\dfrac{y}{P+9}=0\\\\y\left(\dfrac{(P+9)-(P-9)}{P^2-81}\right)=0\\\\y\left(\dfrac{18}{P^2-81}\right)=0\\\\\boxed{y=0}$

The factor multiplying y cannot be zero, so y must be zero.

5 0

3 years ago

The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen

vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.75$

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X = 9)$ when $n = 12$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581$

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X \geq 16)$ when $n = 20$

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 16) = C_{20,16}.(0.75)^{16}.(0.25)^{4} = 0.1897$

$P(X = 17) = C_{20,17}.(0.75)^{17}.(0.25)^{3} = 0.1339$

$P(X = 18) = C_{20,18}.(0.75)^{18}.(0.25)^{2} = 0.0669$

$P(X = 19) = C_{20,19}.(0.75)^{19}.(0.25)^{1} = 0.0211$

$P(X = 20) = C_{20,20}.(0.75)^{20}.(0.25)^{0} = 0.0032$

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1897 + 0.1339 + 0.0669 + 0.0211 + 0.0032 = 0.4148$

c. If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

$E(X) = np$

In this question, we have $n = 22$

$E(X) = 22*0.75 = 16.5$

The closest integer to 16.5 is 17.

7 0

3 years ago

Can yall help me with this WILL GIVE BRAINLIEST

dexar [7]

19 guests because each guest is $2 each according to the question.

6 0

3 years ago

Read 2 more answers

What is 4x -1/2 =x+ 7

gogolik [260]

Answer:

Step-by-step explanation:

Bringing like terms on one side

4x - x = 7 + 1/2

3x = 7.5

x = 7.5/3

x = 2.5

5 0

3 years ago

Read 2 more answers

Emma has 7 bottles: 3 bottles that contain juice, 2 bottles

UNO [17]

Answer: Out of 7 bottles, 2 bottles contain soda. This means that 2 bottles= 29% out of 100%. 7/2 (7 divided by 2) = 0.285. 0.285 can be rounded up to 0.29, meaning that the approximate percentage of the bottles that contain soda is 29%.

4 0

4 years ago