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tia_tia [17]
3 years ago
11

How do you solve a problem like this one 18x^2-15x-18

Mathematics
2 answers:
inna [77]3 years ago
8 0
Ok so this one can be factored like this first:
3(6x^2-5x-6)
Then you have to factor like you normally would for a complex one:
(Put aside the 3 for now just know it's there to make the problem easier)
6x^2-9x+4x-6
3x(2x-3)+2(2x-3)
Adding the 3 put aside now

3(3x+2)(2x-3) is the final factored answer
vfiekz [6]3 years ago
5 0
Solve the problem by factoring, the answer would be: 3(3x+2)(2x−3)


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Jolene lost her wallet at the mall. It had $10 in it when she got home her brother felt bad and gave her $5.75. represent this s
romanna [79]
The ratio is
10 : 5.75
After simplifying the ratio you are left with

1.74 : 1
7 0
3 years ago
Evaluate using suitable property. Write the needed steps. Use proper brackets.<br> 20 x 399 x 5
Reil [10]

Step-by-step explanation:

20 x 399 x 5

= (20×5) × 399

= 100×399

= 39,900

6 0
3 years ago
Evaluate the expression -10-6+4 divided by (-0.5)(-2)
VARVARA [1.3K]

Answer:

-12

Step-by-step explanation:

numerator: -10 - 6 + 4 = -16 + 4 = - 12

denominator: (-0.5)(-2) = 1 Try this on your calculator.

Answer

-12 / 1 = - 12

7 0
4 years ago
A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the
Lubov Fominskaja [6]

Answer:

The required sample size for the new study is 801.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

25% of all adults had used the Internet for such a purpose

This means that \pi = 0.25

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

What is the required sample size for the new study?

This is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.25*0.75)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.25*0.75}

\sqrt{n} = \frac{1.96\sqrt{0.25*0.75}}{0.03}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.25*0.75}}{0.03})^2

n = 800.3

Rounding up:

The required sample size for the new study is 801.

4 0
3 years ago
HELP HELP HELP HELP <br><br> What is the equation of the trend line in the scatter plot ?
NISA [10]

Where is the link to your question? I can't answer thing without a link my guy- :/

3 0
3 years ago
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