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tia_tia [17]
3 years ago
11

How do you solve a problem like this one 18x^2-15x-18

Mathematics
2 answers:
inna [77]3 years ago
8 0
Ok so this one can be factored like this first:
3(6x^2-5x-6)
Then you have to factor like you normally would for a complex one:
(Put aside the 3 for now just know it's there to make the problem easier)
6x^2-9x+4x-6
3x(2x-3)+2(2x-3)
Adding the 3 put aside now

3(3x+2)(2x-3) is the final factored answer
vfiekz [6]3 years ago
5 0
Solve the problem by factoring, the answer would be: 3(3x+2)(2x−3)


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mars1129 [50]

Answer:

Therefore,

(-2)^{3}=-8

Step-by-step explanation:

Simplify

-2^3

(-2)^{3}

It is read as negative 2 raised to the power three,

also it is the cube of negative 2

we know that a^{3}given as

a^{3}=a\times a\times a

so for negative a i.e -a

(-a)^{3}=-a\times -a\times -a

substituting a = 2 we get

(-2)^{3}=-2\times -2\times -2

negative sign multiplied by odd number of times then the sign remains negative.

Therefore,

(-2)^{3}=-8

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3 years ago
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