Name three mass units.! THANKS

A rock is thrown into a swimming pool that is filled with water at a uniform temperature. As the rock moves beneath the pool's s

egoroff_w [7]

Answer:

d. The buoyant force on the rock is constant as it sinks.

Explanation:

The sinking of an object in water can be explained by the Archimedes Principle.

The Archimedes principle states that the buoyant force on a submerged substance is equal to the water displaced by the submerging object. The buoyant force, however, does not change with depth as the substance sinks.

In the given question, when the rock moves beneath the pool, the buoyant force do not change and remains the same that is the amount of water displaced by rock remains the same.

Thus, Option-D is the correct answer.

4 0

4 years ago

If you want to double the kinetic energy of a gas molecule, by what factor must you increase its momentum?A) 16B) 2^(1/2)

worty [1.4K]

Answer: $\sqrt{2}$

The linear momentum $p$ is given by the following equation:

$p=m.v$ (1)

Where $m$ is the mass and $v$ the velocity.

On the other hand, the kinetic energy $K$ is given by:

$K=\frac{p^{2}}{2m}$ (2)

Which is the same as:

$K=\frac{1}{2}m.v^{2}$

Now, if we double the kinetic energy, equation (2) changes to:

$2K=2\frac{p^{2}}{2m}$

$2K=\frac{p^{2}}{m}$ (3)

So, if we want to obtain the kinetic energy as shown in (3), the only option that works is increasing momentum by a factor of $\sqrt{2}$ or $2^{1/2}$ :

Applying this in (2):

$K=\frac{(\sqrt{2}p)^{2}}{2m}$

$K=\frac{(2p)^{2}}{2m}$

$K=\frac{p^{2}}{m}$ >>>As we can see, this equation is the same as equation (3)

Therefore, the correct answer is B

3 0

3 years ago

Which two options are forms of potential energy

lutik1710 [3]

Answer:

Energy is the ability to do work or cause change. There are two kinds of energy – kinetic energy when something is moving, and potential energy, which is energy that is stored and ready to be used. All objects have potential energy or stored energy if they are placed in a certain position.

5 0

4 years ago

Read 2 more answers

What objects did Archimedes use to test the density of the gold crown? How Can a modern investigator identify the elements in pa

alekssr [168]

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6 0

4 years ago

Find the de Broglie wavelength of an electron with a speed of 0.78c. Take relativistic effects into account.

Liono4ka [1.6K]

Answer:

de Broglie wavelength of an electron with speed 0.78 c taking relativistic effects into account is given as:

λ = 1.943 * 10^(-12) m

Explanation:

Given:

v = 0.78 c

we know:

c = speed of light = 3 * 10^8 m/s

mass of electron = m = 9.1 × 10-31 kg

de Broglie wavelength:

In 1924 a French physicist Louis de Broglie assumed that for particles the same relations are valid as for the photon:

(Dual-nature of a particle)

Let the wavelength be = λ

According to de Broglie:

λ = h/p = h/mv

where h is planck's constant = 6.626176 x 10^-34 Js

and p is momentum.

Taking relativistic effects into account, we know that the momentum of the particle changes by a factor 'γ'.

At low speed, γ is almost 1. However, at very high velocity (comparable to light), it has a great effect on momentum.

γ = $\frac{1}{\sqrt{1-\frac{v^{2} }{c^{2} } } }$

γ = 1.6

Now at 0.78 c, considering relativistic effects, we know:

λ = h/γp = h/γ*mv

= (6.62 x 10^(-34))/(1.6*0.78*3*10^(8)*9.1 × 10-31

λ = 1.943 * 10^(-12) m

4 0

3 years ago