If the distance between two charged particles is increased 2.69 times, the ratio of new to old electric force is _______ times t
he old value. (Round your answer to two decimal places).
1 answer:
Answer:
F = K Q1 Q2 / R^2 force between 2 charged partices
F2 / F1 = (R1 / R2)^2 = (1 / 2.69)^2 = .139
F2 = .139 F1
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