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wel
3 years ago
11

A rock is thrown into a swimming pool that is filled with water at a uniform temperature. As the rock moves beneath the pool's s

urface and sinks to the bottom of the pool, which of the following statements is true?
a. The buoyant force on the rock increases as it sinks.
b. The buoyant force on the rock decreases as it sinks.
c. The buoyant force on the rock is zero as it sinks.
d. The buoyant force on the rock is constant as it sinks.
e. The buoyant force on the rock as it sinks is nonzero at first but becomes zero once the terminal velocity is reached.
Physics
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

d. The buoyant force on the rock is constant as it sinks.

Explanation:

The sinking of an object in water can be explained by the Archimedes Principle.

The Archimedes principle states that the buoyant force on a submerged substance is equal to the water displaced by the submerging object. The buoyant force, however, does not change with depth as the substance sinks.

In the given question, when the rock moves beneath the pool, the buoyant force do not change and remains the same that is the amount of water displaced by rock remains the same.

Thus, Option-D is the correct answer.

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Two small, identical conducting spheres repel each other with a force of 0.045 N when they are 0.15 m apart. After a conducting
Levart [38]

Answer:

q_1 = \pm 1.68 \times 10^{-7} C

q_2 = \pm 6.68 \times 10^{-7} C

Explanation:

As we know that the force between two small spheres is given as

F = \frac{kq_1q_2}{r^2}

here we know that

q_1 , q_2 = charges on two small spheres

r = distance between two spheres = 0.15 m

now the force between them is given as

0.045 = \frac{(9\times 10^9)(q_1q_2)}{0.15^2}

q_1q_2 = 1.125 \times 10^{-13}

now when two spheres are connected together then the charge on them is equally divided

q = \frac{q_1+q_2}{2}

now the force between them is given as

F = \frac{k(\frac{q_1+q_2}{2})^2}{0.15^2}

0.070 = \frac{(9\times 10^9)(\frac{q_1+q_2}{2})^2}{0.15^2}

q_1 + q_2 = 8.37\times 10^{-7}

so here we have

q_1 = \pm 1.68 \times 10^{-7} C

q_2 = \pm 6.68 \times 10^{-7} C

5 0
3 years ago
At highway speeds, a particular car is capable of an acceleration of about 1.6 m/s?. At this rate,
kicyunya [14]

Given parameters:

Acceleration of the car = 1.6m/s

Initial speed  = 80km/hr

Final speed  = 110km/hr

Solution:

Time taken to achieve this speed = ?

Solution:

Acceleration is the rate of change of velocity with the time taken.

  Mathematically;

     a  = \frac{V - U}{T}

where a is the acceleration

           V is the final velocity

           U is the initial velocity

           T is the time taken

Now make the unknown time the subject of the expression;

      aT  = V - U

         T = \frac{V - U}{a}  

Convert the given acceleration to km/hr;

       1.6m/s  = 1.6 x \frac{m}{s}  x \frac{1km}{1000m} x \frac{3600s}{1hr} = 5.76km/hr

Input the parameters and solve;

       T = \frac{110 - 80}{5.76}  = 5.2hrs

The time taken is 5.2hrs

5 0
4 years ago
How do you calculate force?
DIA [1.3K]
Force (N) = mass (kg) × acceleration (m/s²)
6 0
4 years ago
List two examples of the following states of matter: solids, liquids, and gases. Please answer in NO LESS THAN 3 complete senten
slavikrds [6]

Answer:

Matter can exist in one of three main states: solid, liquid, or gas. Solid matter is composed of tightly packed particles. A solid will retain its shape; the particles are not free to move around. Liquid matter is made of more loosely packed particles.

Key Takeaways: Examples of Solids, Liquids, and Gases

A solid has a defined shape and volume. A common example is ice. A liquid has a defined volume, but can change state. An example is liquid water.There are four natural states of matter: Solids, liquids, gases and plasma. The fifth state is the man-made Bose-Einstein condensates. In a solid, particles are packed tightly together so they don't move much.

Explanation:

7 0
3 years ago
A researcher measures the thickness of a layer of benzene (nn = 1.50) floating on water by shining monochromatic light onto the
baherus [9]

Answer:

The minimum thickness is t= 8.75*10^{-8} m

Explanation:

generally the equation for thin film interference is mathematically represented as

            2nt = (m + \frac{1}{2} )  \lambda

Where t the  thickness  

           m is any  integer

            n is the refractive index of the film

            \lambda is the wavelength of light

Since we are looking for the thickness we make t the subject of the  formula

          t = \frac{(m+ \frac{1}{2} ) \lambda}{2n}

m= 0 cause the thickness is minimum at m=0

   Substituting values

                    t = \frac{(0 +\frac{1}{2}) 8525*10^{-9} }{2 *1.5}

                       t= 8.75*10^{-8} m

8 0
3 years ago
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