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wel
3 years ago
11

A rock is thrown into a swimming pool that is filled with water at a uniform temperature. As the rock moves beneath the pool's s

urface and sinks to the bottom of the pool, which of the following statements is true?
a. The buoyant force on the rock increases as it sinks.
b. The buoyant force on the rock decreases as it sinks.
c. The buoyant force on the rock is zero as it sinks.
d. The buoyant force on the rock is constant as it sinks.
e. The buoyant force on the rock as it sinks is nonzero at first but becomes zero once the terminal velocity is reached.
Physics
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

d. The buoyant force on the rock is constant as it sinks.

Explanation:

The sinking of an object in water can be explained by the Archimedes Principle.

The Archimedes principle states that the buoyant force on a submerged substance is equal to the water displaced by the submerging object. The buoyant force, however, does not change with depth as the substance sinks.

In the given question, when the rock moves beneath the pool, the buoyant force do not change and remains the same that is the amount of water displaced by rock remains the same.

Thus, Option-D is the correct answer.

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15) On a cold day, you take in 4.2 L (i.e., 4.2 x 10-3 m3) of air into your lungs at a temperature of 0°C. If you hold your brea
Rudiy27

Answer:

4.8L ( i.e 4.8 x 10^-3 m3)

Explanation:

Step 1:

Data obtained from the question.

Initial volume (V1) = 4.2L

Initial temperature (T1) = 0°C

Final temperature (T2) = 37°C

Final volume (V2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature. This is illustrated below

K = °C + 273

T1 = 0°C = 0°C + 273 = 273K

T2 = 37°C = 37°C + 273 = 310K

Step 3:

Determination of the final volume.

Since the pressure is constant,

Charles' Law equation will be applied as shown below:

V1 /T1 = V2/T2

4.2/273 = V2 /310

Cross multiply to express in linear form

273 x V2 = 4.2 x 310

Divide both side by 273

V2 = (4.2 x 310)/273

V2 = 4.8L ( i.e 4.8 x 10^-3 m3)

Therefore, the volume of the air in the lungs at that point is 4.8L ( i.e 4.8 x 10^-3 m3)

3 0
3 years ago
A car drives around a curve with radius 539 m at a speed of 32.0 m/s. The road is banked at 5.00°. The mass of the car is 1.40 ×
HACTEHA [7]

Answer:

f_r = 150.47 N

Explanation:

given,

r = 539 m

v = 32 m/s

road banked at = 5°

∑ F_x

\dfrac{mv^2}{r}= N sin \theta + f_r cos \theta

∑ F_y = 0

0 = N cos \theta - f_r sin \theta - mg

N = \dfrac{f_rsin \theta + mg}{cos \theta}

\dfrac{mv^2}{r}= (\dfrac{f_rsin \theta + mg}{cos \theta})sin \theta + f_r cos \theta

              = f_r sin \theta tan \theta + mg tan \theta + f_r cos \theta

        f_r = \dfrac{\dfrac{mv^2}{r}- mg tan\theta}{sin\theta tan \theta + cos \theta}

         f_r = \dfrac{\dfrac{1.4\times 10^3 \times 32^2}{539}- 1.4\times 10^{3}\times 9.8 \times 0.087}{0.087 \times 0.087 + 0.996}

f_r = 150.47 N

8 0
3 years ago
The current in a resistor is 3.0 A, and its power is 60 W. What is the voltage?
Novosadov [1.4K]

Answer:

20 volts

Explanation:

Use the equation P=VI

60=V(3)

V=20

6 0
2 years ago
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Science Mixtures Question( giving brainly, thanks, and rank of 5 stars.)
vazorg [7]

Answer:

Condensation

Explanation:

That is when water from the air collects as a drop. also can be rain.

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