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KonstantinChe [14]
3 years ago
10

John had $21 to spend on 2 notebooks. After buying them he had $13. How much did each notebook cost?

Mathematics
1 answer:
Eva8 [605]3 years ago
5 0

john had 21.00After buying 2 notebooks he had 13.00

21-13= 8 / 2 =4 each notebook cost 4 dollars.

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Help me please!!!!! I need help with angles
Salsk061 [2.6K]

Answer:

<CFE = 28

<RPQ = 53

Step-by-step explanation:

1)

<CFE + 152 = 180

<CFE = 180 - 152

<CFE = 28

2)

Complementary means the angles add up to 90 so:

<RPQ + 37 = 90

<RPQ = 90 - 37

<RPQ = 53

4 0
3 years ago
Sooo ummm help... 15-p=p-3
bearhunter [10]

Answer:

p = 9

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
2. Find the value of x for which l | | m.​
joja [24]
2x-5=95 due to the alternate interior angles thm so you just add 5 to 95 to get 2x=100 then divide by 2 to get x=50!
7 0
4 years ago
The Better Nutter Butter Co packed 400 lb. of peanut butter into jars holding 2.5 lbs. each. How many jars were used?
Rus_ich [418]

Answer:

160 jars

Step-by-step explanation:

To find how many jars were used, we just need to divide the amount of stuff by the amount of stuff a jar can hold.

400 (the amount of peanut number in pounds) / 2.5 (the amount of peanut butter each jar can hold) = 160.

So, 160 jars were used to package the 400 pounds of peanut butter.

8 0
3 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


5 0
3 years ago
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