Answer with Step-by-step explanation:
We are given that two events A and B are mutually exclusive.




a.For mutually exclusive events,

Therefore, event A can not occurred if event B has occurred because two events can not occur together.
Answer:No, by definition mutually exclusive events cannot occur together.
b.When two events are independent
Then , 

If two events are mutually exclusive then

Then , 
Therefore, 
Hence, we can concluded that events A and B are not independent if they are mutually exclusive.
Answer:Yes, 
Answer:16:18
Step-by-step explanation:
Answer:
Her centripetal acceleration during the turn at each end of the track is 
Step-by-step explanation:
Total distance covered in one round , D= 400 m
Time taken to cover one round , T = 1 min 40 s = 100 sec
Speed of runner , 
Now centripetal acceleration is given by

where 


Thus her centripetal acceleration during the turn at each end of the track is 
I believe 4(x - 3)=32 could help I haven’t done an equation from the unit in months so hopefully that looks familiar to you.
Answer:
1) Fail to reject the Null hypothesis
2) We do not have sufficient evidence to support the claim that the mean distance students traveled to school from their current residence was different for males and females.
Step-by-step explanation:
A university administrator wants to test if there is a difference between the distance men and women travel to class from their current residence. So, the hypothesis would be:

The results of his tests are:
t-value = -1.05
p-value = 0.305
Degrees of freedom = df = 21
Based on this data we need to draw a conclusion about test. The significance level is not given, but the normally used levels of significance are 0.001, 0.005, 0.01 and 0.05
The rule of the thumb is:
- If p-value is equal to or less than the significance level, then we reject the null hypothesis
- If p-value is greater than the significance level, we fail to reject the null hypothesis.
No matter which significance level is used from the above mentioned significance levels, p-value will always be larger than it. Therefore, we fail to reject the null hypothesis.
Conclusion:
We do not have sufficient evidence to support the claim that the mean distance students traveled to school from their current residence was different for males and females.