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spayn [35]
3 years ago
15

Is the sum of two integers always greater than the difference between them? Why or why not?

Mathematics
1 answer:
Sauron [17]3 years ago
4 0
Yes because the gap is one less than the bigger of the two integers, plus you are adding a little bit more to the bigger integer so the sum will always be bigger than the difference.
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Combine and simplify the following radical expression <br><br> ASAP ASAP ASAP ASAP
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Answer:

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Step-by-step explanation:

Our expression is: \frac{1}{3} \sqrt[3]{81}.

Let's focus on the cube root of 81 first. What's the prime factorisation of 81? It's simply: 3 * 3 * 3 * 3, or 3^3*3. Put this in for 81:

\sqrt[3]{81} =\sqrt[3]{3^3*3}=\sqrt[3]{3^3} *\sqrt[3]{3}

We know that the cube root of 3 cubed will cancel out to become 3, but the cube root of 3 cannot be further simplified, so we keep that. Our outcome is then:

\sqrt[3]{3^3} *\sqrt[3]{3}=3\sqrt[3]{3}

Now, let's multiply this by 1/3, as shown in the original problem:

\frac{1}{3}* 3\sqrt[3]{3}=\sqrt[3]{3}

Thus, the answer is \sqrt[3]{3}.

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