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4 years ago

Help!! Question on probability. Wi give brainliest!!

Mathematics

1 answer:

Aleks [24]4 years ago

7 0

Answer:

$P = \frac{5}{282} = 0.0177$

Step-by-step explanation:

First we need to find the total amount of apples in the crate:

Total = 10 + 14 + 4 + 18 = 46 apples

The probability of the first apple being a golden delicious apple is the number of those apples over the total number of apples:

$P(golden) = \frac{N(golden)}{N(total)}$

$P(golden) = \frac{4}{48} = \frac{1}{12}$

Then, the probability of the second apple being a granny Smith apple is the number of those apples over the total number of apples, but now the total number of apples is one less, because one apple was removed from the crate:

$P(granny) = \frac{N(granny)}{N(total)-1}$

$P(granny) = \frac{10}{47}$

The final probability we want is the product of those two probabilities:

$P = P(golden) * P(granny) = \frac{1}{12} \frac{10}{47} = \frac{10}{564} = \frac{5}{282}= 0.0177$

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Which expression is equivalent to (a^-3 b/a^-5 b3)^-3? Assume a=0, b=0.

prohojiy [21]

$Use:\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\\\(ab)^n=a^nb^n$

$\left(\dfrac{a^{-3}b}{a^{-5}b^3}\right)^{-3}=\left(a^{-3-(-5)}b^{1-3}\right)^{-3}=\left(a^{-3+5}b^{-2}\right)^{-3}=\left(a^2b^{-2}\right)^{-3}\\\\=(a^2)^{-3}(b^{-2})^{-3}=a^{2(-3)}b^{-2(-3)}=a^{-6}b^6=\dfrac{b^6}{a^6}$

7 0

3 years ago

1. 7+8-2 .

AnnZ [28]

Answer:

1. 13

2. 11

3. 10

4. 9

5. 12

6. 16

7. 14

8. 40

Step-by-step explanation:

8 0

3 years ago

The total cost of painting of four walls of a square hall at Rs. 40 per sq. m. is Rs. 12000. If the hall contains 600 m³ of air,

astra-53 [7]

Answer:

The height of the hall is 9.375 meters

Step-by-step explanation:

The rate at which the walls of the square hall are painted, R = Rs. 40 per sq. m.

The total cost of painting the square hall, C = Rs. 12,000

The volume of air contained in the hall, V = 600 m³

The surface area of the four walls of the hall, A = C/A

∴ A = Rs. 12,000/(Rs. 40/m²) = 300 m²

Let 's' represent the length of sides of the square hall, and let 'h' represent the height of the square wall, we have;

The volume of the hall, V = s² × h

The surface area of the wall, A = 4 × s × h

Therefore, we get;

A = 300 = 4 × s × h

V = 600 = s² × h

V/A = 600/300 = 2 = s² × h/(4 × s × h) = s/4

s/4 = 2

s = 4 × 2 = 8

The side length of the square hall, s = 8 m.

From the area, A = 4 × s × h, we get;

A = 300 = 4 × 8 × h

h = 300/(4 × 8) = 9.375

The height of the hall, h = 9.375 m.

8 0

3 years ago

BRAINLIEST ASAP! PLEASE HELP ME :)

Afina-wow [57]

Answer:

$\large \boxed{\textbf{30.54 yr}}$

Step-by-step explanation:

For species A,

$P =2000e^{0.05t}$

For species B,

$P =5000e^{0.02t}$

When their populations are equal,

$\begin{array}{rcl}2000e^{0.05t} & = & 5000e^{0.02t}\\e^{0.05t} & = & 2.5e^{0.02t}\\0.05t & = & \ln2.5 + 0.02t\\0.05t & = & 0.9163 + 0.02t\\0.03t & = & 0.9163\\t& = & \dfrac{0.9163}{0.03}\\\\& = & \mathbf{30.54}\\\end{array}\\\text{The populations of species A and B will be the same in $\large \boxed{\textbf{30.54 yr}}$}$

The diagram below shows the population of Species A overtaking that of Species B in about 30.5 yr.

3 0

4 years ago

Can someone help me with all 3

monitta

Answer:

1) 20

2) 60

3) 10

4) 90

Step-by-step explanation:

1. first quartile is the beginning of the box

2. third quartile is the end of the box

3. lowest is the first point of the graph

4. vice versa of 3

6 0

3 years ago