The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y plus 7 equals negative StartFrac

Question

3 years ago

9

tion 2 over 5 EndFraction left-parenthesis x minus 10 right-parenthesis.. What is the standard form of the equation for this line?

2 answers:

user100 [1] · Answer 1 · 2022-03-03T21:54:12+03:00

Answer:

2x + 5y = - 15

Step-by-step explanation:

The line that passes through (–5, –1) and (10, –7) points and the point-slope form of the equation is $y + 7 = - \frac{2}{5}(x - 10)$ .

Now, we have to arrange this in the standard form.

So, $y + 7 = - \frac{2}{5}(x - 10)$

⇒ 5(y + 7) = - 2(x - 10)

⇒ 5y + 35 = - 2x + 20

⇒ 2x + 5y = - 15 (Answer)

Komok [63] · Answer 2 · 2022-03-03T23:45:29+03:00

Komok [63]3 years ago

3 0

Answer:

3rd option: 2x + 5y = -15

Step-by-step explanation:

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