The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y plus 7 equals negative StartFrac
tion 2 over 5 EndFraction left-parenthesis x minus 10 right-parenthesis.. What is the standard form of the equation for this line?
2 answers:
Answer:
2x + 5y = - 15
Step-by-step explanation:
The line that passes through (–5, –1) and (10, –7) points and the point-slope form of the equation is
.
Now, we have to arrange this in the standard form.
So, 
⇒ 5(y + 7) = - 2(x - 10)
⇒ 5y + 35 = - 2x + 20
⇒ 2x + 5y = - 15 (Answer)
Answer:
3rd option: 2x + 5y = -15
Step-by-step explanation:
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