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pogonyaev
3 years ago
11

Simplify this expression 5a/11a

Mathematics
2 answers:
barxatty [35]3 years ago
6 0
You could cross cancel the a and your final answer would be 5/11
choli [55]3 years ago
6 0
For this case we have the following expression:
 5a / 11a
 Rewriting the expression we have:
 (5/11) (a / a)
 We can cancel similar terms.
 Simplifying we have:
 (5/11)
 Answer:
 
The simplified expression is given by:
 
(5/11)
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A box contain 12 balls in which 4 are white 3 are blue and 5 are red.3 balls are drawn at random from the box.find the chance th
Anastasy [175]

Answer:

3/11

Step-by-step explanation:

From the above question, we have the following information

Total number of balls = 12

Number of white balls = 4

Number of blue balls = 3

Number of red balls = 5

We solve this question using combination formula

C(n, r) = nCr = n!/r!(n - r)!

We are told that 3 balls are drawn out at random.

The chance/probability of drawing out 3 balls = 12C3 = 12!/3! × (12 - 3)! = 12!/3! × 9!

= 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1/(3 × 2 × 1) × (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

= 220 ways

The chance of selecting 3 balls at random = 220

To find the chance that all the three balls are selected,

= [Chance of selecting (white ball) × Chance of selecting(blue ball) × Chance of selecting(red balls)]/ The chance/probability of drawing out 3 balls

Chance of selecting (white ball)= 4C1

Chance of selecting(blue ball) = 3C1 Chance of selecting(red balls) = 5C1

Hence,

= [4C1 × 3C1 × 5C1]/ 220

= 60/220

= 6/22

= 3/11

The chance that all three are selected is = 3/11

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3 years ago
A)Agudos<br> B)suplementares <br> C)congruentes<br> D)complementares <br> E)Rasos
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Answer:

The correct answer to this question is complementars

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