Question

Find a round to the nearest tenth 12 22 75 x x=?

Answer 1

Answer:

By law of Sines

$\frac{Sin75^o}{22} =\frac{Sinx}{12}$

• $\frac{Sin75}{22}(12)=\frac{Sinx}{12} (12)$

• $0.5268=Sinx$

• $Sin^(0.5268)=x$

• $x=31.789$

• $x=31.79^o$

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