I belive that it would be 40% or .4
I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have
C(8,3) = 8!/(8-3)!3!
C(8,3) = 56
There are 56 3-person teams that can be formed from the 8 students.
Answer:
(X+2) (X-2) . This is the final answer
Step-by-step explanation:
Solving f(x) = x^2 - 4
A^2 - B^2 is a special case where the original equation before it was foiled is
(A + B) (A - B) because the middle terms will cancel out when foiled.
This means that the equation can be written as
(X + 2)(X - 2) = 0
Each of these you will then set equal to 0 and then solve
X + 2 = 0, X - 2 = 0
X = -2, 2
I hope this helps you! let me now if its right ok <3 :)
Answer:
The coordinates I chose were (0,2) and (4,5)
Step-by-step explanation:
Didn't you already do this question?
Let f(x) = ax³ + 9x² + 4x – 10
g(x) = 0⇒x - 3 = 0
⇒ x = 0 + 3
⇒ x = 3
On dividing f(x) by x - 3, it leaves a remainder 5.
Now keeping, f(3) = 5
⇒a(3)³ + 9(3)² + 4(3) - 10 = 5
⇒ a × 27 + 9 × 9 + 4 × 3 - 10 = 5
⇒ 27a + 81 + 12 - 10 = 5
⇒ 81 + 12 - 10 - 5 = 27a
⇒ 81 + 12 - 15 = 27a
⇒ 93 - 15 = 27a
⇒ 78 = 27a
⇒ a = 27/78
⇒ a = 0.3461
