Suppose a triangle has sides a, b, and c let theta be the angle opposite the side of length a. If cos theta < 0 what must be
2 answers:
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If a2 -2ab + b2 = 9 and a
then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3
Answer:
The general rule is
Step-by-step explanation:
Arithmetic sequence:
In an arithmetic sequence, the difference between consecutive terms is always the same, and this difference is called common difference.
The general rule of an arithmetic sequence is given by:
In which is the first term and d is the common difference.
We can also find the nth term as a function of a term m, using:
a3 = -12 and a8 = -37
First we find the common difference. So
So
Finding the first term:
Since
So the general rule is:
Check the picture below. You can pretty much just count the units off the grid.
