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Ulleksa [173]
3 years ago
6

write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

ne point, and a third linear that does not intersect y=x^2. Explain how you found the linear equations.
Mathematics
1 answer:
Liula [17]3 years ago
5 0

We know that y = x^2 is a parabola, concave up, with vertex in the origin (0,0)

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

  • The horizontal line y = 4 intercepts the parabola twice: the system y = x^2,\ y = 4 is solved by x^2=4 \implies x = \pm 2
  • The horizontal line y=0 intercepts the parabola only once: the system is y=x^2,\ y=0 which yields x^2=0\implies x=0 which is a repeated solution
  • The horizontal line y=-5 intercepts the parabola only once: the system is y=x^2,\ y=-5 which yields x^2=-5 which is impossible, because a squared number can't be negative.
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