All categories

3 years ago

Part B

Mathematics

1 answer:

SVEN [57.7K]3 years ago

3 0

Answer:

$500

Step-by-step explanation:

substitute the values for X & S in the equation from part A:

y=20x + 0.15s

x=($20x25) + (0.15x$0)

= $500

You might be interested in

Put these in order starting with the smallest:

AleksandrR [38]

Answer:

1 to the power of 8= 8

2 to the power of 4 =16

5 squared =25

3 to the power of 3 =27

Step-by-step explanation:

2 to the power of 4 =16

3 to the power of 3 =27

1 to the power of 8= 8

7 0

3 years ago

What are the possible values of x if (4x - 5)2 = 49? Check all that apply.<br> uw we we

kogti [31]

Answer:

x = - $\frac{1}{2}$ , x = 3

Step-by-step explanation:

Given

(4x - 5)² = 49 ( take the square root of both sides )

4x - 5 = ± $\sqrt{49}$ = ± 7 ( add 5 to both sides )

4x = 5 ± 7, thus

4x = 5 - 7 = - 2 ( divide both sides by 4 )

x = $\frac{-2}{4}$ = - $\frac{1}{2}$

4x = 5 + 7 = 12 ( divide both sides by 4 )

x = 3

As a check

Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.

x = - $\frac{1}{2}$

left side = (- 2 - 5)² = (- 7)² = 49 = right side ⇒ solution

x = 3

left side = (12 - 5)² = 7² = 49 = right side ⇒ solution

7 0

3 years ago

How do u graph x>-6 on a line graph?

erastova [34]

Ok so if -6 is the y intercept you look for -6 on the y axis and use rise over run up one over one until you can't plot anymore and then down one over one and do the same thing did that help you Phil?

5 0

2 years ago

Read 2 more answers

The slope of a line is 2 and the point (1, 1) lies on the line. What is the y-intercept of this line? (0, -1) (0, 5) (-2, 0)

artcher [175]

Answer:

(0, -1)

Step-by-step explanation:

It's helpful if we think of slope in the context of rise over run.

Since the point (1, 1) lies on the line, because of the slope 2, if we subtract x by 1 to get to x = 0, then we'll be subtracting y by 2.

By that logic, the answer must be (0, -1).

4 0

2 years ago

Graph ARST with vertices R(6, 6), S(3, -6), and T(0, 3) and its image after a

padilas [110]

Answer:

The answer is the second figure and the vertices of Δ R'S'T' are:

R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)

Step-by-step explanation:

* Lets revise some transformation

- If point (x , y) reflected across the x-axis

∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

∴ Its image is (-x , y)

- If point (x , y) reflected across the line y = x

∴ Its image is (y , x)

- If point (x , y) reflected across the line y = -x

∴ Its image is (-y , -x)

- Now we can solve the problem

∵ R = (6 , 6) , S = (3 , -6) , T = (0 , 3), they are the vertices of ΔRST

- The triangle RST is reflected over the y-axis

- According to the rule above the signs of x-coordinates will change

∵ R = (6 , 6)

∴ Its image is (-6 , 6)

∵ S = (3 , -6)

∴ Its image is (-3 , -6)

∵ T = (0 , 3)

∴ Its image is (0 , 3)

* Now lets look to the figure to find the correct answers

- The image of Δ RST is ΔR'S'T'

∵ The vertices of the image of ΔRST are:

R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)

* The answer is the second figure

7 0

3 years ago